amorphous wrote:
In the figure, what is the area of triangle BCD given that the area of triangle ADE is 16 & the area of triangle CDE is 12?
A) 12
B) 16
C) 20
D) 28
E) Cannot be determined
∆ADC is comprised of 2 regions: ∆ADE and ∆CDE
We're told that ∆ADE and ∆CDE have areas 16 ans 12 respectively.
So, the area of ∆ADC = 16 + 12 = 28
First recognize that ∆ADC and ∆BCD both have the same base.
Also, if we let h = the height of ∆ADC, then ∆BCD also has height h
area of triangle = (base)(height)/2So, if ∆ADC and ∆BCD have the same base and the same height, then they must have the same area.
So, if the area of ∆ADC is 28, then the area of ∆BCD must also be 28
Answer: D
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Brent Hanneson - founder of Greenlight Test Prep