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In the figure above what is the area [#permalink]
Expert's post 00:00

Question Stats: 100% (00:22) correct 0% (00:00) wrong based on 9 sessions
Attachment: square.png [ 3.17 KiB | Viewed 321 times ]

In the figure above what is the area of the square $$QRST$$?

A. $$25$$

B. $$20 \sqrt{2}$$

C. $$25 \sqrt{2}$$

D. $$50$$

E. $$50 \sqrt{2}$$
[Reveal] Spoiler: OA

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Director Joined: 20 Apr 2016
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WE: Engineering (Energy and Utilities)
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Re: In the figure above what is the area [#permalink]
Carcass wrote:
Attachment:
square.png

In the figure above what is the area of the square $$QRST$$?

A. $$25$$

B. $$20 \sqrt{2}$$

C. $$25 \sqrt{2}$$

D. $$50$$

E. $$50 \sqrt{2}$$

Here we need to find the side of the square to find out area.

since it is right angled $$\triangle$$ so by Pythagoras theorem,

$$QT = \sqrt{5^2 + 5^2} = \sqrt {50} = 5\sqrt 2$$

Now the area of the square QTRS = $$(5\sqrt 2)^2 = 50$$
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Rules for Posting https://greprepclub.com/forum/rules-for ... -1083.html Re: In the figure above what is the area   [#permalink] 04 Aug 2018, 03:43
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