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In the figure above what is the area

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In the figure above what is the area [#permalink] New post 04 Aug 2018, 02:35
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Attachment:
square.png
square.png [ 3.17 KiB | Viewed 911 times ]


In the figure above what is the area of the square \(QRST\)?

A. \(25\)

B. \(20 \sqrt{2}\)

C. \(25 \sqrt{2}\)

D. \(50\)

E. \(50 \sqrt{2}\)
[Reveal] Spoiler: OA

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Re: In the figure above what is the area [#permalink] New post 04 Aug 2018, 03:43
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Carcass wrote:
Attachment:
square.png


In the figure above what is the area of the square \(QRST\)?

A. \(25\)

B. \(20 \sqrt{2}\)

C. \(25 \sqrt{2}\)

D. \(50\)

E. \(50 \sqrt{2}\)


Here we need to find the side of the square to find out area.

since it is right angled \(\triangle\) so by Pythagoras theorem,

\(QT = \sqrt{5^2 + 5^2} = \sqrt {50} = 5\sqrt 2\)

Now the area of the square QTRS = \((5\sqrt 2)^2 = 50\)
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Re: In the figure above what is the area   [#permalink] 04 Aug 2018, 03:43
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