Carcass wrote:
This was one of the most controversial questions due to the poor quality of the geometry figure.
Now I have updated with a good one figure.
Regards
@Carcass Plz can u look into the diagram attached
When the area of triangle is said to \(10\pi\) are we actually considering the the area of the arc AB and arc AC? I didn't really understood the reasoning
However, this is how I solved,
@Carcass kindly provide ur valuable feedback::Let first find the angle COA and angle DOB
i.e. \(\frac{{\angle COA}}{360} = \frac{{40\pi}}{{100\pi}}\) (each shaded area is 40 pi and the area of the circle is 100 pi)
or \(\angle COA = 144\)
Now \(\angle COD = 180 -144 =36\) (DA is the a straight line and diameter of the circle)
Similarly it can be proved \(\angle AOB = 36\)
Hence for the two \(\triangle\)'s combined
it can be written as \(a + b + 36 + c + d + 36 =360\)
or \(a + b + c + d = 288\)
Attachments
#GREpracticequestion In the figure above, the diameter of the circle is 20.jpg [ 15.74 KiB | Viewed 6738 times ]
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