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In the figure above, the area of ABC is 35. What is the

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In the figure above, the area of ABC is 35. What is the [#permalink] New post 08 Oct 2017, 00:46
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In the figure above, the area of \(\triangle\) ABC is 35. What is the length of DC?

enter your value

[Reveal] Spoiler: OA
8

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Re: In the figure above, the area of ABC is 35. What is the [#permalink] New post 09 Oct 2017, 01:50
Carcass wrote:


Attachment:
triangle.jpg


In the figure above, the area of \(\triangle\) ABC is 35. What is the length of DC?

enter your value

[Reveal] Spoiler: OA
8



Given
\(\triangle\) ABC = 35

I.e \(\frac{1}{2} * BC * 7 = 35\)

or BC = 10

Now in \(\triangle\) BCD,

\(DC^2= \sqrt{(10^2 - 6^2)}\) = 64

or DC = 8
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Re: In the figure above, the area of ABC is 35. What is the [#permalink] New post 09 Oct 2017, 07:28
Another way to solve it is to notice that one leg of BCD is 6 and the hypotenuse is 10, and given that the triangle is a right triangle, we can use the Pitagorean triplet 3:4:5, where each of the sides is doubled. Indeed, in this case we would have 6:x:10 and x = 8.
Re: In the figure above, the area of ABC is 35. What is the   [#permalink] 09 Oct 2017, 07:28
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