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# In the figure above, LMNO and GHJK are rectangles where

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In the figure above, LMNO and GHJK are rectangles where [#permalink]  20 Aug 2019, 07:55
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#GREpracticequestion In the figure above.jpg [ 27.76 KiB | Viewed 142 times ]

In the figure above, $$LMNO$$ and $$GHJK$$ are rectangles where $$GH = \frac{1}{2}LM$$ and $$HJ= \frac{1}{2} MN$$. What fraction of the region bounded by $$LMNO$$
is NOT shaded?

(A) $$\frac{1}{4}$$

(B) $$\frac{1}{3}$$

(C) $$\frac{1}{2}$$

(D) $$\frac{2}{3}$$

(E) $$\frac{3}{4}$$
[Reveal] Spoiler: OA

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Re: In the figure above, LMNO and GHJK are rectangles where [#permalink]  07 Sep 2019, 19:54
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Carcass wrote:
Attachment:
#GREpracticequestion In the figure above.jpg

In the figure above, $$LMNO$$ and $$GHJK$$ are rectangles where $$GH = \frac{1}{2}LM$$ and $$HJ= \frac{1}{2} MN$$. What fraction of the region bounded by $$LMNO$$
is NOT shaded?

(A) $$\frac{1}{4}$$

(B) $$\frac{1}{3}$$

(C) $$\frac{1}{2}$$

(D) $$\frac{2}{3}$$

(E) $$\frac{3}{4}$$

Here,

Let LM = 4 and MN = 8

therefore, GH = $$\frac{1}{2} * LM = \frac{1}{2} * 4 = 2$$

and HJ = $$\frac{1}{2}* MN = \frac{1}{2} * 8 = 4$$

Area of GHJK = $$2*4 = 8$$ [ Area of Rectangle = length * breadth]

and Area of LMNO = $$4 *8 = 32$$

Area of the unshaded region = $$32 -8 = 24$$
Therefore,

fraction of the region bounded by $$LMNO$$is NOT shaded = $$\frac{24}{32} = \frac{3}{4}$$
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Re: In the figure above, LMNO and GHJK are rectangles where   [#permalink] 07 Sep 2019, 19:54
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# In the figure above, LMNO and GHJK are rectangles where

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