ExplanationAttachment:

#GREpracticequestion In the figure above, if the square inscribed in the circle.jpg [ 16.38 KiB | Viewed 2391 times ]
If the area of the square is 16, that means each side is 4-

Now we do have an isosceles triangle with two equal side

\(x:x:x\sqrt{2}\)

\(4 : 4 : 4 \sqrt{2}\)

So the side of the triangle which is also the circumference. Therefore, the radius is half that \(\frac{4 \sqrt{2}}{2} = 2 \sqrt{2}\) and the area of the circle is \(\pi r^2=\pi(2 \sqrt{2} )^2 = 8 \pi\)

The area we are looking for is \(\frac{8\pi - 16}{4} = 2\pi - 4\)

B is correct

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Sandy

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