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Moderator  Joined: 18 Apr 2015
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Kudos [?]: 1148 , given: 5456

In the figure above, if the area of the inscribed rectangula [#permalink]
Expert's post 00:00

Question Stats: 100% (00:47) correct 0% (00:00) wrong based on 4 sessions
Attachment: #GREpracticequestion In the figure above, if the area of the inscribed.jpg [ 6.53 KiB | Viewed 129 times ]

In the figure above, if the area of the inscribed rectangular region is 32, then the circumference of the circle is

(A) $$20 \pi$$

(B) $$4 \pi \sqrt{5}$$

(C) $$4 \pi \sqrt{3}$$

(D) $$2 \pi \sqrt{5}$$

(E) $$2 \pi \sqrt{3}$$
[Reveal] Spoiler: OA

_________________ Director Joined: 03 Sep 2017
Posts: 521
Followers: 1

Kudos [?]: 344  , given: 66

Re: In the figure above, if the area of the inscribed rectangula [#permalink]
1
KUDOS
The area of the rectangular is $$x*2x = 32$$, from which we get x = 4 (we exclude x = -4 because a side of a rectangular cannot have a negative length.

Then, using Pitagora's theorem we can find the length of the hypotenuse of the triangle, which is half of the rectangular and we get it equal to $$\sqrt(80) = 4sqrt(5)$$.

Finally, the circumference of the circle is given by $$2r*\pi$$ where 2r is the diameter that in this case equals $$4sqrt(5)$$.

Thus, the circumference is equal to $$4\pi\sqrt(5)$$. Answer B! Re: In the figure above, if the area of the inscribed rectangula   [#permalink] 29 Sep 2017, 07:49
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