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# In the figure above, if JL and KL are parallel to the x and

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In the figure above, if JL and KL are parallel to the x and [#permalink]  14 May 2018, 14:20
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Question Stats:

73% (00:40) correct 26% (00:47) wrong based on 23 sessions
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#GREpracticequestion if JL and KL are parallel to the x .jpg [ 13.44 KiB | Viewed 798 times ]

In the figure above, if JL and KL are parallel to the x and y-axes, respectively, what is the area of $$\Delta JKL$$?

(A) 4.5

(B) 5

(C) 7.5

(D) 8

(E) 15
[Reveal] Spoiler: OA

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Joined: 26 Jan 2018
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Kudos [?]: 134 [1] , given: 3

Re: In the figure above, if JL and KL are parallel to the x and [#permalink]  15 May 2018, 04:31
1
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Base JL is // to x axis hance change in value of y axis gives its value.

Height KL is // to y axis hence change in value of x axis gives it value

Hence base = 5
Height = 3
Area of trianlge = 1/2*base*height

=7.5
Intern
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Kudos [?]: 31 [1] , given: 30

Re: In the figure above, if JL and KL are parallel to the x and [#permalink]  02 Jan 2020, 05:54
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KUDOS
For area of JKL we need base and height of triangle

Base of the triangle = JL = 5 units (Change in X co-ordinate from -4 to +1)
Height of the triangle = KL = 3 units (Change in Y co-ordinate from -1 to +2)

Area = (1/2)*Base*Height = (1/2)*5*3 = 7.5

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Kudos [?]: 187 [0], given: 5

Re: In the figure above, if JL and KL are parallel to the x and [#permalink]  03 Jan 2020, 06:34
X-axis and Y-axis intersect each other at right angle. We can see that JLK is also a right angle.
which means that JL is parallel to the x axis and KL is parallel to the y-axis.
The co-ordinates of L become (1,-1)

Now JL = 5 units and KL = 3 units.

Area = $$\frac{1}{2} \times 5 \times 3$$ = 7.5

OA, C
Carcass wrote:
Attachment:
#GREpracticequestion if JL and KL are parallel to the x .jpg

In the figure above, if JL and KL are parallel to the x and y-axes, respectively, what is the area of $$\Delta JKL$$?

(A) 4.5

(B) 5

(C) 7.5

(D) 8

(E) 15

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Re: In the figure above, if JL and KL are parallel to the x and   [#permalink] 03 Jan 2020, 06:34
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