Jan 25 10:00 PM PST  11:00 PM PST Everything you need to know about the GRE, plus study tips and free resources. The perfect companion to your Magoosh GRE prep course. Jan 30 10:00 PM PST  11:00 PM PST This admissions guide will help you plan your best route to a PhD by helping you choose the best programs your goals, secure strong letters of recommendation, strengthen your candidacy, and apply successfully. Jan 31 08:00 PM PST  09:00 PM PST To help you prepare for test day, I created the following sets of downloadable flashcards (in pdf format): 174 flashcards covering every formula, concept and strategy needed for the quantitative sections of the GRE. Feb 02 10:00 PM PST  11:00 PM PST Target Test Prep is giving 1 lucky winner 4 months of FREE access to our toprated GRE Quant course. Our giveaway contest is open for 10 days only, so enter today at https://gre.targettestprep.com/giveaway for your chance to levelup your prep! Feb 04 06:30 PM EST  10:30 PM EST Attend one of our GRE TechFree Classes. Tuesdays at 6:30  9:30 PM
Author 
Message 
TAGS:


Founder
Joined: 18 Apr 2015
Posts: 9396
Followers: 195
Kudos [?]:
2288
[1]
, given: 8892

In the figure above, ABCD is a square with sides equal to [#permalink]
04 Aug 2017, 07:52
1
This post received KUDOS
Question Stats:
44% (02:50) correct
55% (02:59) wrong based on 43 sessions
Attachment:
#GRepracticequestion In the figure above, ABCD is a square with sides equal to 1,.jpg [ 26.23 KiB  Viewed 1794 times ]
In the figure above, ABCD is a square with sides equal to 1, AFC is an arc of a circle centered at B, and AEC is an arc of a circle centered at D. What is the area of rhombus AECF? A. 2  \(\sqrt{2}\) B. \(\sqrt{2}\)  1 C. \(\sqrt{2}(2  \sqrt{2})\) D. \(\sqrt{2}\) E. 1 + \(\sqrt{2}\)
_________________
Need Practice? 20 Free GRE Quant Tests available for free with 20 Kudos GRE Prep Club Members of the Month: Each member of the month will get three months free access of GRE Prep Club tests.




Director
Joined: 03 Sep 2017
Posts: 519
Followers: 2
Kudos [?]:
396
[3]
, given: 66

Re: In the figure above, ABCD is a square with sides equal to [#permalink]
19 Sep 2017, 08:10
3
This post received KUDOS
If the side of the square is equal to 1 its diagonal is \(sqrt(2)\), which coincides with the rhombus main diagonal.
To find the smaller one, I exploit the fact that DE = 1 since it is a radius of the semicircle so as AD, side of the square. Thus, the smaller diagonal is equal to the diagonal of the square minus twice DF, i.e. \(EF=sqrt(2)2*(sqrt(2)1)\).
Given the two diagonals we can compute the area of the rhombus as \(\frac{sqrt(2)*[sqrt(2)2*(sqrt(2)1]}{2}=sqrt(2)1\). Thus, the answer is B!



Intern
Joined: 21 Apr 2017
Posts: 3
Followers: 0
Kudos [?]:
1
[1]
, given: 3

Re: In the figure above, ABCD is a square with sides equal to [#permalink]
30 Sep 2017, 22:34
1
This post received KUDOS
fraction[sqrt(2)*[sqrt(2)2*(sqrt(2)1]]/[2]=sqrt(2)1



Intern
Joined: 07 Jan 2019
Posts: 30
Followers: 0
Kudos [?]:
2
[0], given: 0

Re: In the figure above, ABCD is a square with sides equal to [#permalink]
09 Jan 2019, 13:23
done thank you



Manager
Joined: 18 Jun 2019
Posts: 124
Followers: 0
Kudos [?]:
23
[0], given: 62

Re: In the figure above, ABCD is a square with sides equal to [#permalink]
07 Sep 2019, 17:30
Hi,
Can somebody please post a better solution to this?
Thanks!




Re: In the figure above, ABCD is a square with sides equal to
[#permalink]
07 Sep 2019, 17:30





