It is currently 18 Nov 2018, 08:06
My Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

In the figure above, AB is a line segment.

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Moderator
Moderator
User avatar
Joined: 18 Apr 2015
Posts: 4907
Followers: 74

Kudos [?]: 976 [0], given: 4497

CAT Tests
In the figure above, AB is a line segment. [#permalink] New post 19 Mar 2018, 11:16
Expert's post
00:00

Question Stats:

100% (00:53) correct 0% (00:00) wrong based on 8 sessions
Attachment:
xy.jpg
xy.jpg [ 12.4 KiB | Viewed 241 times ]


In the figure above, AB is a line segment. What is the value of \(\frac{x - y}{x + y}\) ?

(A) \(\frac{5}{24}\)

(B) \(\frac{1}{4}\)

(C) \(\frac{7}{16}\)

(D) \(\frac{11}{24}\)

(E) \(\frac{7}{13}\)
[Reveal] Spoiler: OA

_________________

Get the 2 FREE GREPrepclub Tests

1 KUDOS received
Intern
Intern
Joined: 20 Mar 2018
Posts: 34
GRE 1: Q164 V150
Followers: 1

Kudos [?]: 24 [1] , given: 2

Re: In the figure above, AB is a line segment. [#permalink] New post 20 Mar 2018, 22:44
1
This post received
KUDOS
Since AB is a line segment, the angles on both of its sides would be of 180 degrees.

3x = 5y = 180
x=60 and y= 36

x-y= 24
x+y = 96

Ans: B
Re: In the figure above, AB is a line segment.   [#permalink] 20 Mar 2018, 22:44
Display posts from previous: Sort by

In the figure above, AB is a line segment.

  Question banks Downloads My Bookmarks Reviews Important topics  


GRE Prep Club Forum Home| About| Terms and Conditions and Privacy Policy| GRE Prep Club Rules| Contact

Powered by phpBB © phpBB Group

Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.