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# In the figure above, 0 is the center of the circle and arc S

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In the figure above, 0 is the center of the circle and arc S [#permalink]  22 May 2020, 10:16
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100% (01:12) correct 0% (00:00) wrong based on 6 sessions
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#greprepclub In the figure above, 0 is the center of the circle.jpg [ 21.97 KiB | Viewed 65 times ]

In the figure above, 0 is the center of the circle and arc SRT has length $$2\pi$$. If the circumference of the circle is $$12\pi$$, what is the value of x + y ?

(A) 60

(B) 90

(C) 120

(D) 150

(E) It cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: In the figure above, 0 is the center of the circle and arc S [#permalink]  22 May 2020, 23:04
length of arc = theta / 360 * circumference of circle
2π = theta / 360 * 12π
On solving this, we get, theta = 60.
Thus, 180-60 = 120.
Re: In the figure above, 0 is the center of the circle and arc S   [#permalink] 22 May 2020, 23:04
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