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# In the figure, ABCD is a rectangle, and the area of ∆ACE is

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In the figure, ABCD is a rectangle, and the area of ∆ACE is [#permalink]  01 Oct 2018, 13:32
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100% (01:01) correct 0% (00:00) wrong based on 13 sessions
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#GREpracticequestion In the figure, ABCD is a rectangle, and the area.jpg [ 18.09 KiB | Viewed 1990 times ]

In the figure, ABCD is a rectangle, and the area of ∆ACE is 10. What is the area of the rectangle?

(A) 18
(B) 22.5
(C) 36
(D) 44
(E) 45
[Reveal] Spoiler: OA

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Intern
Joined: 07 Sep 2018
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Kudos [?]: 2 [0], given: 5

Re: In the figure, ABCD is a rectangle, and the area of ∆ACE is [#permalink]  02 Oct 2018, 06:36
solution pls??
Intern
Joined: 26 Mar 2017
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Kudos [?]: 12 [1] , given: 53

Re: In the figure, ABCD is a rectangle, and the area of ∆ACE is [#permalink]  02 Oct 2018, 10:42
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Hi,

Area of traingle ACE is 10. Calculate the 'height' of the traingle to get the width of the rectangle. Length of the rectangle is given as 5+4=9.

Height of triangle

1/2*5*h =10
h =10*2/5=4

Area of rectangle = 9*4=36
Intern
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Re: In the figure, ABCD is a rectangle, and the area of ∆ACE is [#permalink]  04 Sep 2019, 22:34
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KUDOS
Area of triangle ACE is 10. Calculate the 'height' of the triangle = width of the rectangle. Length of the rectangle is given: 5+4=9.

Height:

1/2*5*h =10
h =10*2/5=4

Area of rectangle = 9*4=36
Re: In the figure, ABCD is a rectangle, and the area of ∆ACE is   [#permalink] 04 Sep 2019, 22:34
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