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Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. In the diagram, JL = 4 and JK = 6.  Question banks Downloads My Bookmarks Reviews Important topics
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Senior Manager Joined: 20 May 2014
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In the diagram, JL = 4 and JK = 6. [#permalink] 00:00

Question Stats: 58% (00:48) correct 41% (00:00) wrong based on 12 sessions In the diagram, JL = 4 and JK = 6. A. The quantity in Column A is greater
B. The quantity in Column B is greater
C. The two quantities are equal
D. The relationship cannot be determined from the information given

Kudos for correct solution.

[Reveal] Spoiler:
Attachment: gqgpp_img4.png [ 1.45 KiB | Viewed 775 times ]

Attachment: gqgpp_img4b.png [ 1012 Bytes | Viewed 774 times ]
[Reveal] Spoiler: OA Director Joined: 03 Sep 2017
Posts: 520
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Kudos [?]: 356  , given: 66

Re: In the diagram, JL = 4 and JK = 6. [#permalink]
1
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I am not sure Magoosh explanation is right because they use two different figures in the text and in the answer. If we keep using the figure in the question, the answer should be B.

Indeed, we have one leg equal to 4 and hypotenuse equal to 6. Then a triangle has maximal area when it is right-angled. Thus, when its second leg is equal to 36-16 = 2sqrt(5). In this case, the area of the triangle is equal to 4sqrt(5) that is less than 12.

If this is the maximal area, there is no way to get something greater than 12 so that quantity B should be greater.
Manager Joined: 03 Dec 2017
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Re: In the diagram, JL = 4 and JK = 6. [#permalink]
Bunuel can you explain this,
thank you Director Joined: 20 Apr 2016
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WE: Engineering (Energy and Utilities)
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Re: In the diagram, JL = 4 and JK = 6. [#permalink]
2
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wongpcla wrote:
Bunuel can you explain this,
thank you

Let me explain this,

We know in triangle with sides A,B and c

Difference of any two sides < Third side < Sum of any two sides

Now consider the triangle above,

The maximum value of the third side must be less 10, or else the triangle rule wont be applicable

Now if we consider the third side =10 (assuming maximum value)

then Area = 1/2 * base * Altitude

= 1/2 * 4 * 10 = 20

Now the minimum value of the third side must be greater than 2.

SO let us take the value of third side = 2

Then Area = 1/2 * 4 * 2 = 4.

Now the area of the triangle is either greater than 12 or less than 12

Hence the option is D. (The diagram in geometry section are not drawn to scale unless specified. Here it looks like right angle triangle but nothing is mentioned so we cannot assume.)

Let me know if you need further clarification
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Manager Joined: 03 Dec 2017
Posts: 65
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Kudos [?]: 16 , given: 20

Re: In the diagram, JL = 4 and JK = 6. [#permalink]
pranab01 wrote:
wongpcla wrote:
Bunuel can you explain this,
thank you

Let me explain this,

We know in triangle with sides A,B and c

Difference of any two sides < Third side < Sum of any two sides

Now consider the triangle above,

The maximum value of the third side must be less 10, or else the triangle rule wont be applicable

Now if we consider the third side =10 (assuming maximum value)

then Area = 1/2 * base * Altitude

= 1/2 * 4 * 10 = 20

Now the minimum value of the third side must be greater than 2.

SO let us take the value of third side = 2

Then Area = 1/2 * 4 * 2 = 4.

Now the area of the triangle is either greater than 12 or less than 12

Hence the option is D. (The diagram in geometry section are not drawn to scale unless specified. Here it looks like right angle triangle but nothing is mentioned so we cannot assume.)

Let me know if you need further clarification

thank you very much.
now it is clear Re: In the diagram, JL = 4 and JK = 6.   [#permalink] 07 Dec 2017, 22:04
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