It is currently 25 Jun 2019, 11:50
My Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

In the course of an experiment, 95 measurements were recorde

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
2 KUDOS received
GRE Prep Club Legend
GRE Prep Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4809
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 120

Kudos [?]: 1910 [2] , given: 397

In the course of an experiment, 95 measurements were recorde [#permalink] New post 23 Dec 2015, 18:53
2
This post received
KUDOS
Expert's post
00:00

Question Stats:

50% (01:31) correct 49% (01:26) wrong based on 65 sessions
Attachment:
#GREpracticequestion In the course of an experiment, 95 measurements were recorded.jpg
#GREpracticequestion In the course of an experiment, 95 measurements were recorded.jpg [ 22.67 KiB | Viewed 1689 times ]


In the course of an experiment, 95 measurements were recorded, and all of the measurements were integers. The 95 measurements were then grouped into 7 measurement intervals. The graph above shows the frequency distribution of the 95 measurements by measurement interval.

Quantity A
Quantity B
The average (arithmetic mean) of the 95 measurements
The median of the 95 measurements


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Practice Questions
Question: 2
Page: 155
Difficulty: hard
[Reveal] Spoiler: OA

_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

3 KUDOS received
GRE Prep Club Legend
GRE Prep Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4809
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 120

Kudos [?]: 1910 [3] , given: 397

Re: course of an experiment, 95 measurements were recorded [#permalink] New post 23 Dec 2015, 19:16
3
This post received
KUDOS
Expert's post
Now here we have a frequency plot for 95 measurement. If we observe the first 3 columns of the graph we have 15, 35 and 15 in the ranges 1-5, 6-10, 11-15.

Now median of 95 is the 48th number so it must lie in 6 - 10 range.

Now the way to find average is to assume that all the numbers in a single column is the same i.e the mid point. So all the number of the column 1-5 is 3. So now we take these and multiply by frequency.

\(\frac{(3*15 + 35*8 + 15*13)}{(15 + 35+ 15)}\) = 8 considering t just the first 3 columns now as we add more measurements of higher values the average increases further. Hence Average > Median for this experiment.

PS: A useful tip if the distribution is balanced i.e symmetric about the midpoint. The average is close to median. If it is skewed to left (like in the figure above) the average is greater than median and if its skewed to right the average is less than the median.
_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

Intern
Intern
Joined: 28 Mar 2016
Posts: 11
Followers: 0

Kudos [?]: 1 [0], given: 0

Re: course of an experiment, 95 measurements were recorded [#permalink] New post 29 Mar 2016, 09:07
Now the way to find average is to assume that all the numbers in a single column is the same i.e the mid point. So all the number of the column 1-5 is 3. So now we take these and multiply by frequency.

^^^^ I don't get this part I thought 1-5 is about 13 according to graph, also where does 3*15 + 35 * 18 + 15 * 13 come from? where does the 15+35 + 15 come from?
2 KUDOS received
GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 2021
Followers: 62

Kudos [?]: 1835 [2] , given: 9

CAT Tests
Re: course of an experiment, 95 measurements were recorded [#permalink] New post 20 Apr 2017, 05:46
2
This post received
KUDOS
Expert's post
sandy wrote:
Image

In the course of an experiment, 95 measurements were recorded, and all of the measurements were integers. The 95 measurements were then grouped into 7 measurement intervals. The graph above shows the frequency distribution of the 95 measurements by measurement interval.

Quantity A
Quantity B
The average (arithmetic mean) of the 95 measurements
The median of the 95 measurements


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


Tough/time-consuming question.

QUANTITY A
To find the mean, we must add all 95 values.
Notice that, that each interval, there are 5 possible values for each data point.
For example, the first entry is 1-5, which means the each of the 15 data points can be 1, 2, 3, 4, or 5 (NOTE: the data points are all INTEGERS)
So, which value do we use?
If all 15 data points are 1, then the mean will be different from the case where are 15 data points are 5.
So, let's see what happens if each data point is the MINIMUM POSSIBLE VALUE

1-5 interval: there are 15 data points. So if each data point is 1, then the SUM = (15)(1) = 15
6-10 interval: there are 35 data points. So if each data point is 6, then the SUM = (35)(6) = 210
11-15 interval: there are 15 data points. So if each data point is 11, then the SUM = (15)(11) = 165
16-20 interval: there are 12 data points. So if each data point is 16, then the SUM = (12)(16) = 192
21-25 interval: there are 10 data points. So if each data point is 21, then the SUM = (10)(21) = 210
26-30 interval: there are 5 data points. So if each data point is 26, then the SUM = (5)(26) = 130
31-35 interval: there are 3 data points. So if each data point is 31, then the SUM = (3)(31) = 93

So, the SUM of all 95 data points = 15 + 210 + 165 + 192 + 210 + 130 + 93
= 1015
So, MEAN = 1015/95 ≈ 10.6
Since we used the smallest possible value for each interval, we can conclude that the SMALLEST possible value of Quantity A is 10.6

QUANTITY B
The median of the 95 data points will be the MIDDLEMOST value when all of the values are arranged in ASCENDING ORDER
So, the median will equal the 48th value when all of the values are arranged in ASCENDING ORDER
In the 1-5 interval, there are 15 data points.
In the 6-10 interval, there are 35 data points.
At this point, we've already accounted for 50 data points (15 + 35 = 50).
This means the 48th value will be in the 6-10 interval.
So, the median of the set must be 6, 7, 8, 9, or 10

So, the largest possible value of Quantity B is 10
And, the smallest possible value of Quantity A is 10.6

So, we can be certain that Quantity A is greater.

Answer:
[Reveal] Spoiler:
A

_________________

Brent Hanneson – Creator of greenlighttestprep.com
Image
Sign up for my free GRE Question of the Day emails

Director
Director
Joined: 09 Nov 2018
Posts: 508
Followers: 0

Kudos [?]: 27 [0], given: 1

Re: course of an experiment, 95 measurements were recorded [#permalink] New post 14 Nov 2018, 09:02
sagnik242 wrote:
Now the way to find average is to assume that all the numbers in a single column is the same i.e the mid point. So all the number of the column 1-5 is 3. So now we take these and multiply by frequency.

^^^^ I don't get this part I thought 1-5 is about 13 according to graph, also where does 3*15 + 35 * 18 + 15 * 13 come from? where does the 15+35 + 15 come from?

Yes, it is confusing to me too.
GRE Prep Club Legend
GRE Prep Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4809
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 120

Kudos [?]: 1910 [0], given: 397

Re: course of an experiment, 95 measurements were recorded [#permalink] New post 14 Nov 2018, 13:31
Expert's post
AE wrote:
sagnik242 wrote:
Now the way to find average is to assume that all the numbers in a single column is the same i.e the mid point. So all the number of the column 1-5 is 3. So now we take these and multiply by frequency.

^^^^ I don't get this part I thought 1-5 is about 13 according to graph, also where does 3*15 + 35 * 18 + 15 * 13 come from? where does the 15+35 + 15 come from?

Yes, it is confusing to me too.


If you want to calculate the exact average of 95 values you need all 95 values explicitly. Now we do not have that but we know that 13 values of the 95 values lie between 1 and 5 (inclusive).

It could be 13 1s' or 13 5s' we dont know. Hence we take the average value from the range to calculate the values so \(13 *3\), 3 being the average

\(13*3=39\)

Now in worst case the sum is \(13*1=13\).

In best case the sum is \(13*5=65\).

39 is exactly in the middle. It is not accurate but a close enough approximation.

It is important to note that in statistics we will always have 'losses'.

If we had all 13 numbers we could tell exactly all of their properties however we want to represent the whole data set with minimum numbers.


In this case 13 is the frequency (i.e. number of times) 1 is the lower bound and 5 is the upper bound. We described 13 number using only 3 numbers.
_________________

Sandy
If you found this post useful, please let me know by pressing the Kudos Button

Try our free Online GRE Test

Intern
Intern
Joined: 10 Jan 2018
Posts: 10
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: course of an experiment, 95 measurements were recorded [#permalink] New post 28 Apr 2019, 07:01
PS: A useful tip if the distribution is balanced i.e symmetric about the midpoint. The average is close to median. If it is skewed to left (like in the figure above) the average is greater than median and if its skewed to right the average is less than the median.[/quote]

Hello
Correct me if I'm wrong but the graph above is skewed TO RIGHT (not the left as you said)
Intern
Intern
Joined: 09 Dec 2018
Posts: 10
Followers: 0

Kudos [?]: 6 [0], given: 8

Re: course of an experiment, 95 measurements were recorded [#permalink] New post 28 Apr 2019, 08:38
The graph is skewed to the right, and the skew pulls the mean along with it, but generally leaves the median alone. So in this right-skewed case, the mean is greater than the median. Not hard, not time-consuming.

Hope this helps.
Re: course of an experiment, 95 measurements were recorded   [#permalink] 28 Apr 2019, 08:38
Display posts from previous: Sort by

In the course of an experiment, 95 measurements were recorde

  Question banks Downloads My Bookmarks Reviews Important topics  


cron

GRE Prep Club Forum Home| About| Terms and Conditions and Privacy Policy| GRE Prep Club Rules| Contact

Powered by phpBB © phpBB Group

Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.