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In rectangle ABCD, sides AD and BC have been divided into se
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Carcass
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In rectangle ABCD, sides AD and BC have been divided into se [#permalink] New post  28 Jul 2018, 03:54
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In rectangle ABCD, sides AD and BC have been divided into segments of equal length as shown.

Quantity A
Quantity B
The length of EF
The length of GC


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

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pranab223
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Re: In rectangle ABCD, sides AD and BC have been divided into se [#permalink] New post  28 Jul 2018, 23:25
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Carcass wrote:

In rectangle ABCD, sides AD and BC have been divided into segments of equal length as shown.

Quantity A
Quantity B
The length of EF
The length of GC


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E


Let M and F be connected, so we have two right angled \(\triangle\) i. e. \(\triangle EMF\) and \(\triangle GCD\).



Since it is a rectangle , so BC = AD and AB = CD

Now we can see the length of the base \(GD > ME\), so the hypotenuse for the \(\triangle EMP > \triangle GCD\)

I.e. Length of EF < Length of GC.


** Try taking some values for the rectangle, the result will be the same
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AE
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Re: In rectangle ABCD, sides AD and BC have been divided into se [#permalink] New post  18 Jan 2019, 20:03
I did with by add E and point between G and A.
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AE
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Re: In rectangle ABCD, sides AD and BC have been divided into se [#permalink] New post  18 Jan 2019, 20:07
pranab01 wrote:

Now we can see the length of the base \(GD > ME\), so the hypotenuse for the \(\triangle EMP > \triangle GCD\)

I.e. Length of EF < Length of GC.


Please fix the typo.
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Re: In rectangle ABCD, sides AD and BC have been divided into se [#permalink] New post  18 Jun 2022, 14:44
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