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In rectangle ABCD, sides AD and BC have been divided into se

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In rectangle ABCD, sides AD and BC have been divided into se [#permalink]  28 Jul 2018, 03:54
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80% (01:12) correct 20% (00:58) wrong based on 10 sessions
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In rectangle ABCD, sides AD and BC have been divided into segments of equal length as shown.

 Quantity A Quantity B The length of EF The length of GC

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E
[Reveal] Spoiler: OA

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WE: Engineering (Energy and Utilities)
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Re: In rectangle ABCD, sides AD and BC have been divided into se [#permalink]  28 Jul 2018, 23:25
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Carcass wrote:

In rectangle ABCD, sides AD and BC have been divided into segments of equal length as shown.

 Quantity A Quantity B The length of EF The length of GC

A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.

Kudos for R.A.E

Let M and F be connected, so we have two right angled $$\triangle$$ i. e. $$\triangle EMF$$ and $$\triangle GCD$$.

Since it is a rectangle , so BC = AD and AB = CD

Now we can see the length of the base $$GD > ME$$, so the hypotenuse for the $$\triangle EMP > \triangle GCD$$

I.e. Length of EF < Length of GC.

** Try taking some values for the rectangle, the result will be the same
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Re: In rectangle ABCD, sides AD and BC have been divided into se [#permalink]  18 Jan 2019, 20:03
I did with by add E and point between G and A.
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Re: In rectangle ABCD, sides AD and BC have been divided into se [#permalink]  18 Jan 2019, 20:07
pranab01 wrote:

Now we can see the length of the base $$GD > ME$$, so the hypotenuse for the $$\triangle EMP > \triangle GCD$$

I.e. Length of EF < Length of GC.

Re: In rectangle ABCD, sides AD and BC have been divided into se   [#permalink] 18 Jan 2019, 20:07
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