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# In rectangle ABCD below, and Find the following. AB=5,AF=7,

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In rectangle ABCD below, and Find the following. AB=5,AF=7, [#permalink]  26 May 2019, 01:51
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In rectangle ABCD below, AB=5,AF=7, FD=3. Find the following.

(a) Area of ABCD

(b) Area of triangle AEF

(c) Length of BD

(d) Perimeter of ABCD

Attachment:

#GREexcercise In rectangle ABCD below.jpg [ 16.07 KiB | Viewed 1949 times ]

[Reveal] Spoiler: OA
(a) 50 (b) 17.5 (c) 5 $$\sqrt{5}$$ (d) 30

Math Review
Question: 10
Page: 260
Difficulty: medium

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Re: In rectangle ABCD below, and Find the following. AB=5,AF=7, [#permalink]  27 May 2019, 12:49
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Expert's post
Carcass wrote:
In rectangle ABCD below, AB=5,AF=7, FD=3. Find the following.

(a) Area of ABCD

(b) Area of triangle AEF

(c) Length of BD

(d) Perimeter of ABCD

Attachment:
#GREexcercise In rectangle ABCD below.jpg

[Reveal] Spoiler: OA
(a) 50 (b) 17.5 (c) 5 $$\sqrt{5}$$ (d) 30

Math Review
Question: 10
Page: 260
Difficulty: medium

GIVEN: AB = 5, AF = 7, and FD = 3
Add the information to the diagram

(a) Area of ABCD
Area of rectangle = (base)(height) = (10)(5) = 50

(b) Area of triangle AEF

Area of triangle = (base)(height)/2
= (7)(5)/2 = 17.5

(c) Length of BD

Since ∆ABD is a RIGHT triangle, we can apply the Pythagorean Theorem.
We get: 5² + 10² = (side BD)²
Simplify: 25 + 100 = (side BD)²
Simplify: 125 = (side BD)²
Solve: side BD = √125 = √25 x √5 = 5√5

(d) Perimeter of ABCD
Perimeter = 5 + 10 + 5 + 10 = 30

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com

Re: In rectangle ABCD below, and Find the following. AB=5,AF=7,   [#permalink] 27 May 2019, 12:49
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