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# In one can of mixed nuts, 30% of the mixture is peanuts. In

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In one can of mixed nuts, 30% of the mixture is peanuts. In [#permalink]  08 Jan 2018, 15:08
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75% (02:58) correct 25% (02:15) wrong based on 4 sessions

In one can of mixed nuts, 30% of the mixture is peanuts. In another can of mixed nuts that is one-half the size of the first one, 40% is peanuts. If both cans are emptied into the same bowl, what percent of the mixed nuts in the bowl is peanuts?

A. $$16 \frac{2}{3} %$$

B. $$20 %$$

C. $$25 %$$

D. $$33 \frac{1}{3} %$$

E. $$40 %$$

Kudo for the right answer and explanation.
[Reveal] Spoiler: OA

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Re: In one can of mixed nuts, 30% of the mixture is peanuts. In [#permalink]  09 Jan 2018, 00:54
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lets assume:
The first can is 10 pounds then 30% of 10= 3 pounds comprises of peanuts
The second can is 1/2 of 1st can= 1/2* 10= 5 pounds of which 40% is peanuts
Hence 0.4*5 = 2 pounds comprises of peanuts
The bowl comprises of total 15 pounds of nuts of which 2+3=5 pounds is peanuts
% of peanuts in the bowl= 5/15*100= 33.33% (d)
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This is my response to the question and may be incorrect. Feel free to rectify any mistakes

Re: In one can of mixed nuts, 30% of the mixture is peanuts. In   [#permalink] 09 Jan 2018, 00:54
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