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In a town, 80% of the men are registered voters [#permalink]
26 Dec 2017, 07:01
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In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? enter your value




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Re: In a town, 80% of the men are registered voters [#permalink]
26 Dec 2017, 07:02
This is a numeric entry question. Why the OA is A?? Please, review it. Thank you
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Re: In a town, 80% of the men are registered voters [#permalink]
26 Dec 2017, 07:12
Carcass wrote: This is a numeric entry question. Why the OA is A??
Please, review it.
Thank you The fraction of total that is men is 6/7 (Make a double matrix and solve it accordingly). this is the answer I didnt have a file to upload



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Re: In a town, 80% of the men are registered voters [#permalink]
26 Dec 2017, 11:03
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sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\).
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Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 04:22
sandy wrote: sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\). the stem doesn't indicate approximation, and the answer is 6/7, please check it out.



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Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 04:35
Peter wrote: sandy wrote: sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\). the stem doesn't indicate approximation, and the answer is 6/7, please check it out. 6/7 is actually = 86/100. So i guess sandy's answer is right.



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Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 04:35
sandy wrote: sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\). thank you!



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Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 05:24
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sameer93 wrote: sandy wrote: sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\). thank you! If the stem SPECIFICALLY indicates approximation, then 86/100 is correct. The following is my calculation: 0.8m +0.66w= 0.78 (m+w) then we got 0.8m+0.66w = 0.78m +0.78w and we do some simplication here, we got 0.02m= 0.12w and this means that 2m= 12w > m=6w then m:w = 6:1 m/w+m(total population)= 6/7 is it clear now? no approximation invloved here. SO answer 6/7 would be better, never put approximation value if the stem doesn't specify.



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Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 05:57
Peter wrote: sandy wrote: sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\). the stem doesn't indicate approximation, and the answer is 6/7, please check it out. I don't understand would you like to explain it? :/



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Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 05:59
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[quote=
you can see the above illustration, otherwise, i don't know what to say.



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Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 14:36
@Peter is right in this regard. The stem DOES NOT mention (at all) approximation. Not only that, if you solve the question the solution is not approximate but is a known number and it is \(\frac{6}{7}\). The problem even if it seems a word problem (it is indeed) can be solved like a mixture problem of two parts. \(80 X + 66 Y = 78 (X + Y)\) Solving the equation we obtain \(\frac{X}{Y} = \frac{6}{1}\). Our X = 6 and the total of men + women are 6+1 = 7 So, the number of men is 6 over 7 or \(\frac{6}{7}\)
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Re: In a town, 80% of the men are registered voters
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