Author 
Message 
TAGS:


Intern
Joined: 06 Oct 2017
Posts: 9
Followers: 0
Kudos [?]:
3
[0], given: 2

In a town, 80% of the men are registered voters [#permalink]
26 Dec 2017, 07:01
Question Stats:
50% (02:02) correct
50% (01:57) wrong based on 4 sessions
In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? enter your value




Moderator
Joined: 18 Apr 2015
Posts: 5185
Followers: 77
Kudos [?]:
1040
[0], given: 4676

Re: In a town, 80% of the men are registered voters [#permalink]
26 Dec 2017, 07:02
This is a numeric entry question. Why the OA is A?? Please, review it. Thank you
_________________
Get the 2 FREE GREPrepclub Tests



Intern
Joined: 06 Oct 2017
Posts: 9
Followers: 0
Kudos [?]:
3
[0], given: 2

Re: In a town, 80% of the men are registered voters [#permalink]
26 Dec 2017, 07:12
Carcass wrote: This is a numeric entry question. Why the OA is A??
Please, review it.
Thank you The fraction of total that is men is 6/7 (Make a double matrix and solve it accordingly). this is the answer I didnt have a file to upload



GMAT Club Legend
Joined: 07 Jun 2014
Posts: 4750
WE: Business Development (Energy and Utilities)
Followers: 93
Kudos [?]:
1663
[2]
, given: 396

Re: In a town, 80% of the men are registered voters [#permalink]
26 Dec 2017, 11:03
2
This post received KUDOS
sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\).
_________________
Sandy If you found this post useful, please let me know by pressing the Kudos Button
Try our free Online GRE Test



Manager
Joined: 27 Sep 2017
Posts: 112
Followers: 1
Kudos [?]:
29
[0], given: 4

Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 04:22
sandy wrote: sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\). the stem doesn't indicate approximation, and the answer is 6/7, please check it out.



Intern
Joined: 06 Oct 2017
Posts: 9
Followers: 0
Kudos [?]:
3
[0], given: 2

Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 04:35
Peter wrote: sandy wrote: sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\). the stem doesn't indicate approximation, and the answer is 6/7, please check it out. 6/7 is actually = 86/100. So i guess sandy's answer is right.



Intern
Joined: 06 Oct 2017
Posts: 9
Followers: 0
Kudos [?]:
3
[0], given: 2

Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 04:35
sandy wrote: sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\). thank you!



Manager
Joined: 27 Sep 2017
Posts: 112
Followers: 1
Kudos [?]:
29
[1]
, given: 4

Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 05:24
1
This post received KUDOS
sameer93 wrote: sandy wrote: sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\). thank you! If the stem SPECIFICALLY indicates approximation, then 86/100 is correct. The following is my calculation: 0.8m +0.66w= 0.78 (m+w) then we got 0.8m+0.66w = 0.78m +0.78w and we do some simplication here, we got 0.02m= 0.12w and this means that 2m= 12w > m=6w then m:w = 6:1 m/w+m(total population)= 6/7 is it clear now? no approximation invloved here. SO answer 6/7 would be better, never put approximation value if the stem doesn't specify.



Intern
Joined: 06 Oct 2017
Posts: 9
Followers: 0
Kudos [?]:
3
[0], given: 2

Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 05:57
Peter wrote: sandy wrote: sameer93 wrote: In a town, 80% of the men are registered voters and 66% of the women are registered voters. if 78% of the total population is a registered voter, what fraction of the population is Men? Let assume there are 100 people in town. Let \(x\) be the men and women \(100  x\). Total voters = 78% of 100 = 78. Number of men voters = \(0.8 \times x\) Number of women voters = \(0.66 \times (100  x)= 66  0.66x\) Total voters men and women = 0.14x + 66 = 78. x= 12/ 0.14 = 86 approx. Hence number of men is 86 and women is 14. Hence fraction of men in population is \(\frac{86}{100}\). the stem doesn't indicate approximation, and the answer is 6/7, please check it out. I don't understand would you like to explain it? :/



Manager
Joined: 27 Sep 2017
Posts: 112
Followers: 1
Kudos [?]:
29
[1]
, given: 4

Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 05:59
1
This post received KUDOS
[quote=
you can see the above illustration, otherwise, i don't know what to say.



Moderator
Joined: 18 Apr 2015
Posts: 5185
Followers: 77
Kudos [?]:
1040
[0], given: 4676

Re: In a town, 80% of the men are registered voters [#permalink]
27 Dec 2017, 14:36
@Peter is right in this regard. The stem DOES NOT mention (at all) approximation. Not only that, if you solve the question the solution is not approximate but is a known number and it is \(\frac{6}{7}\). The problem even if it seems a word problem (it is indeed) can be solved like a mixture problem of two parts. \(80 X + 66 Y = 78 (X + Y)\) Solving the equation we obtain \(\frac{X}{Y} = \frac{6}{1}\). Our X = 6 and the total of men + women are 6+1 = 7 So, the number of men is 6 over 7 or \(\frac{6}{7}\)
_________________
Get the 2 FREE GREPrepclub Tests




Re: In a town, 80% of the men are registered voters
[#permalink]
27 Dec 2017, 14:36





