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In a regular n-sided polygon, the measure of a single angle

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GMAT Club Legend
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In a regular n-sided polygon, the measure of a single angle [#permalink] New post 26 Mar 2018, 16:05
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Question Stats:

100% (00:55) correct 0% (00:00) wrong based on 10 sessions
In a regular n-sided polygon, the measure of a single angle is \(\frac{(n-2) \times 180}{n}\). The degree measure of an angle in a regular 10-sided polygon is how much greater than the degree measure of an angle in a regular 6-sided polygon?

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[Reveal] Spoiler: OA
24

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Re: In a regular n-sided polygon, the measure of a single angle [#permalink] New post 26 Mar 2018, 21:29
This looks like a geometry problem, but it's also basically a function problem. They tell you a function (the measure of the angle) and then ask you to subtract the function with one input from the function with another input. Anyway.

Basically, just plug in 10 into the equation, and plug in 6 into the equation, and subtract the latter from the former. Let's go.

((10 - 2)x180)/10 = 8x18 = 144

((6 - 2)x180)/6 = 120

So 144 - 120 = 24. Done.
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GMAT Club Legend
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User avatar
Joined: 07 Jun 2014
Posts: 4749
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 93

Kudos [?]: 1659 [0], given: 396

CAT Tests
Re: In a regular n-sided polygon, the measure of a single angle [#permalink] New post 04 Apr 2018, 16:03
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Explanation

Find the measure of an angle in a regular 10-sided polygon by plugging 10 into the given formula: \(\frac{(10-2)\times 180}{10}\)=144°.

Then do the same for a regular 6-sided polygon by plugging 6 into the given formula: \(\frac{(6-2)\times 180}{6}\)=120°. Finally, 144 – 120 = 24.
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Re: In a regular n-sided polygon, the measure of a single angle   [#permalink] 04 Apr 2018, 16:03
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In a regular n-sided polygon, the measure of a single angle

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