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In a history class that consisted of 30 students, the number

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In a history class that consisted of 30 students, the number [#permalink] New post 09 May 2018, 10:00
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In a history class that consisted of 30 students, the number of seniors was 3 more than twice the number of juniors, and \(\frac{3}{10}\) of the students were neither juniors nor seniors.


Quantity A
Quantity B
The number of juniors in the class
6


A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: In a history class that consisted of 30 students, the number [#permalink] New post 11 May 2018, 11:05
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more than twice the 3 number makes the question confusing. looks like there is a typo.
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Re: In a history class that consisted of 30 students, the number [#permalink] New post 11 May 2018, 20:02
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Quote:
more than twice the 3 number makes the question confusing. looks like there is a typo.
yes 3 was at a wrong place. it is fixed now

total number of students =\(30\)
total number of students that are not juniors or seniors = \(3/10 * 30 = 9\)
no of juniors + no of seniors = \(21\)
Let j = no of juniors
Let s = no of seniors
we have \(j+s = 21\).........(i)
from question we get, \(2*j + 3 = s\)......(ii)

replace the value of s from eqn (ii) in (i)
\(j+ 2j +3 = 21\)
solve for \(j; j=6\)
option c
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Re: In a history class that consisted of 30 students, the number   [#permalink] 11 May 2018, 20:02
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In a history class that consisted of 30 students, the number

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