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In a history class that consisted of 30 students, the number

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In a history class that consisted of 30 students, the number [#permalink]  09 May 2018, 10:00
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Question Stats:

75% (01:09) correct 25% (01:37) wrong based on 4 sessions
In a history class that consisted of 30 students, the number of seniors was 3 more than twice the number of juniors, and $$\frac{3}{10}$$ of the students were neither juniors nor seniors.

 Quantity A Quantity B The number of juniors in the class 6

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Joined: 26 Jan 2018
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Kudos [?]: 104 [1] , given: 3

Re: In a history class that consisted of 30 students, the number [#permalink]  11 May 2018, 11:05
1
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more than twice the 3 number makes the question confusing. looks like there is a typo.
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Joined: 07 Jan 2018
Posts: 553
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Kudos [?]: 477 [1] , given: 84

Re: In a history class that consisted of 30 students, the number [#permalink]  11 May 2018, 20:02
1
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Quote:
more than twice the 3 number makes the question confusing. looks like there is a typo.
yes 3 was at a wrong place. it is fixed now

total number of students =$$30$$
total number of students that are not juniors or seniors = $$3/10 * 30 = 9$$
no of juniors + no of seniors = $$21$$
Let j = no of juniors
Let s = no of seniors
we have $$j+s = 21$$.........(i)
from question we get, $$2*j + 3 = s$$......(ii)

replace the value of s from eqn (ii) in (i)
$$j+ 2j +3 = 21$$
solve for $$j; j=6$$
option c
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This is my response to the question and may be incorrect. Feel free to rectify any mistakes

Re: In a history class that consisted of 30 students, the number   [#permalink] 11 May 2018, 20:02
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