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In a garden, there are only red, yellow, and blue flowers.

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In a garden, there are only red, yellow, and blue flowers. [#permalink] New post 19 Jun 2017, 11:49
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Question Stats:

73% (01:24) correct 26% (01:16) wrong based on 23 sessions


In a garden, there are only red, yellow, and blue flowers. One–third of the flowers are red, and 40 percent are blue. One flower is chosen at random.

Quantity A
Quantity B
The probability that the
flower chosen is not red
The probability the
flower chosen is not
yellow


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.
[Reveal] Spoiler: OA

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Re: In a garden, there are only red, yellow, and blue flowers. [#permalink] New post 16 Sep 2017, 23:42
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The probability that the chosen flower is not red is equal to 1-1/3 = 0.67, i.e. the probability of choosing whatever flower minus the probability of choosing a red flower. The probability that the chosen flower is not yellow is equal to the sum of the probability of the flower being red or blue, i.e. 1/3 + 0.4 = 0.73. Thus the answer is B!
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Re: In a garden, there are only red, yellow, and blue flowers. [#permalink] New post 22 Sep 2017, 21:56
Carcass wrote:


In a garden, there are only red, yellow, and blue flowers. One–third of the flowers are red, and 40 percent are blue. One flower is chosen at random.

Quantity A
Quantity B
The probability that the
flower chosen is not red
The probability the
flower chosen is not
yellow


A) Quantity A is greater.
B) Quantity B is greater.
C) The two quantities are equal.
D) The relationship cannot be determined from the information given.



Let take total number of flowers be 90 (Since it is divisible by 3 and 40% x 90 gives an integer , however the total number can be of any value as long as itis divisible by 3 and multiply with 40% gives an integer)

\(\frac{1}{3}\)*90 = 30 Red flowers

and 40% = 90*.4 = 36 blue flowers.

Therefore we have 24 yellow flowers (since 90 - (30+36))

Now The probability that the
flower chosen is not red = \(\frac{60}{90}\)(Since yellow =24 and Blue = 36 ie 24+46 =60)

And The probability the flower chosen is not yellow = \(\frac{66}{90}\)(Since Red =30and Blue = 36 ie 24+36 =66)

Therefore \(\frac{60}{90}\) < \(\frac{66}{90}\)
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Re: In a garden, there are only red, yellow, and blue flowers.   [#permalink] 22 Sep 2017, 21:56
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In a garden, there are only red, yellow, and blue flowers.

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