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# In a certain year, Minnesota produced

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In a certain year, Minnesota produced [#permalink]  08 Jan 2019, 10:25
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Question Stats:

100% (02:01) correct 0% (00:00) wrong based on 4 sessions
In a certain year, Minnesota produced $$\frac{2}{3}$$ and Michigan produced $$\frac{1}{6}$$ of all the iron ore produced in the United States. If all the other states combined produced 18 million tons that year, how many million tons did Minnesota produce that year?

(A) 27

(B) 36

(C) 54

(D) 72

(E) 162
[Reveal] Spoiler: OA

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WE: Engineering (Energy and Utilities)
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Re: In a certain year, Minnesota produced [#permalink]  09 Jan 2019, 05:27
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Carcass wrote:
In a certain year, Minnesota produced $$\frac{2}{3}$$ and Michigan produced $$\frac{1}{6}$$ of all the iron ore produced in the United States. If all the other states combined produced 18 million tons that year, how many million tons did Minnesota produce that year?

(A) 27

(B) 36

(C) 54

(D) 72

(E) 162

Explanation::

As Minnesota produced $$\frac{2}{3}$$ and Michigan produced $$\frac{1}{6}$$, therefore the remaining state = $$\frac{1}{6}$$ = 18 million

Now , Minnesota produced $$\frac{2}{3}$$ i.e. = $$\frac{4}{6}$$ = 4 * 18 = 72 Million ( $$\frac{2}{3}$$= can also be written as $$\frac{4}{6}$$ and $$\frac{1}{6}$$ = 18 million)
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Re: In a certain year, Minnesota produced   [#permalink] 09 Jan 2019, 05:27
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