It is currently 03 Jul 2020, 14:15
My Tests

The 4th of July -

The Independence Day FULL Access to the Tests !!


Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

In a 200 member association

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
1 KUDOS received
Manager
Manager
Joined: 17 Aug 2019
Posts: 242
Followers: 2

Kudos [?]: 30 [1] , given: 59

In a 200 member association [#permalink] New post 18 May 2020, 06:31
1
This post received
KUDOS
00:00

Question Stats:

66% (02:37) correct 33% (01:49) wrong based on 21 sessions
In a 200 member association consisting of men and women, exactly 20% of men and exactly 25 % women are homeowners. What is the least number of members who are homeowners?

A.49
B.47
C.45
D.43
E.41


What is the best strategy to use here ?
[Reveal] Spoiler: OA
Manager
Manager
Joined: 09 Mar 2020
Posts: 130
Followers: 0

Kudos [?]: 119 [0], given: 10

Re: In a 200 member association [#permalink] New post 18 May 2020, 21:37
It is given that there are 200 members and 20% men and 25% female are homeowners.
To find the least number of members, we need to know that when the lesser the number, more lesser the resulting percent will be. Thus, if we take a large number for 20% and a small number for 25%, we can get the least amount possible.
In this case, 180*0.2 = 36 and 20*0.25 = 5, thus 36+5=41, option E.
Hence, always take a smaller number for larger percentage.
Moderator
Moderator
Joined: 16 Oct 2019
Posts: 63
Followers: 0

Kudos [?]: 49 [0], given: 21

Re: In a 200 member association [#permalink] New post 18 May 2020, 21:56
sukrut96 wrote:
It is given that there are 200 members and 20% men and 25% female are homeowners.
To find the least number of members, we need to know that when the lesser the number, more lesser the resulting percent will be. Thus, if we take a large number for 20% and a small number for 25%, we can get the least amount possible.
In this case, 180*0.2 = 36 and 20*0.25 = 5, thus 36+5=41, option E.
Hence, always take a smaller number for larger percentage.


Is there any thinking behind dividing 200 into 180 and 20??
1 KUDOS received
Manager
Manager
Joined: 09 Mar 2020
Posts: 130
Followers: 0

Kudos [?]: 119 [1] , given: 10

Re: In a 200 member association [#permalink] New post 18 May 2020, 22:38
1
This post received
KUDOS
vndnjn wrote:
sukrut96 wrote:
It is given that there are 200 members and 20% men and 25% female are homeowners.
To find the least number of members, we need to know that when the lesser the number, more lesser the resulting percent will be. Thus, if we take a large number for 20% and a small number for 25%, we can get the least amount possible.
In this case, 180*0.2 = 36 and 20*0.25 = 5, thus 36+5=41, option E.
Hence, always take a smaller number for larger percentage.


Is there any thinking behind dividing 200 into 180 and 20??


By using trial and error method, I reached this number.
Started with 140, 60 and tried till 180 and 20.
Also we need an integer value, so even integers will work well.
2 KUDOS received
Intern
Intern
Joined: 27 Jun 2020
Posts: 6
Followers: 0

Kudos [?]: 4 [2] , given: 3

Re: In a 200 member association [#permalink] New post 29 Jun 2020, 11:49
2
This post received
KUDOS
The way I would do it is also trail and error, but not random trail and error. As sukrut96 points out we want the 25% group (women) to be as small as possible. As we know that at least one person in each group is a home owner because there are both men and women in the association and the percentages are positive.
Starting with one woman who is a home owner --> 3 women are not --> there are 200-4=196 men left in the group.
We also know that 0.2x = x/5 --> the number of remaining men should be divisable by 5, and 196 is not. Then:
2 female homeowners --> 8 women in total --> 192 not divisible by 5
3 --> 12 --> 188
4 --> 16 --> 184
5 --> 20 --> 180
180 is divisible by 5 so here we stop.
180/5 + 5 = 41
Re: In a 200 member association   [#permalink] 29 Jun 2020, 11:49
Display posts from previous: Sort by

In a 200 member association

  Question banks Downloads My Bookmarks Reviews Important topics  


cron

GRE Prep Club Forum Home| About| Terms and Conditions and Privacy Policy| GRE Prep Club Rules| Contact

Powered by phpBB © phpBB Group

Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.