Carcass wrote:

In 1999, Diana read 10 English books and 7 French books. In 2000, she read twice as many French books as English books. If 60% of the books that she read during the two years were French, how many books did she read in 2000?

A) 16

B) 26

C) 32

D) 39

E) 48

In 2000, she read twice as many French books as English books.Let x = number of English books read in 2000

So, 2x = number of French books read in 2000

If 60% of the books that she read during the two years were French, how many books did she read in 2000? Diana read 17 books (10 English and 7 French) in 1999, and she read 3x books (x English and 2x French) in 2000

So,

17 + 3x = the TOTAL number of books she read in two years

FRENCH BOOKS

Diana read 7 French books in 1999 and 2x French books in 2000

So, she read a TOTAL of

2x + 7 French books

If French books comprise 60% of the books she read in 2 years, we can write: (

2x + 7)/(

17 + 3x) = 60/100

Cross multiply to get: 100(

2x + 7) = 60(

17 + 3x)

Expand both sides to get: 200x + 700 = 1020 + 180x

Subtract 180x from both sides to get: 20x + 700 = 1020

Subtract 700 from both sides to get: 20x = 320

Solve: x = 320/20 =

16BE CAREFUL! x = number of English books read in 2000, and we want the TOTAL number of books read in 2000

3x = TOTAL number of books read in 2000

3(

16) = 48, so Diana read a TOTAL of 48 books in 2000

Answer: E

Cheers,

Brent

_________________

Brent Hanneson – Creator of greenlighttestprep.com

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