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# In 1986 the median home price in Danbury was approximately h

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In 1986 the median home price in Danbury was approximately h [#permalink]  25 Feb 2017, 09:03
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100% (00:49) correct 0% (00:00) wrong based on 29 sessions

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#GREpracticequestion In 1986 the median home price in Danbury.jpg [ 151.99 KiB | Viewed 2267 times ]

* Housing cost consists of a mortgage payment, real estate taxes, utilities and hazard insurance.

In 1986 the median home price in Danbury was approximately how many times the median home price in Trenton?

A) $$3$$

B) $$2$$

C) $$1\frac{2}{3}$$

D) $$1\frac{1}{2}$$

E) $$\frac{1}{3}$$
[Reveal] Spoiler: OA

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Joined: 07 Jun 2014
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Re: In 1986 the median home price in Danbury was approximately h [#permalink]  04 Mar 2017, 17:34
1
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Expert's post
Explanation

The median home price in Danbury = $95950. The median home price in Trenton =$66000

So $$X \times 66000 = 95950.$$

So $$X \approx 1\frac{1}{2}$$

Hence option D is correct.
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Manager
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Re: In 1986 the median home price in Danbury was approximately h [#permalink]  29 Jan 2018, 21:49
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sandy wrote:
Explanation

The median home price in Danbury = $95950. The median home price in Trenton =$66000

So $$X \times 66000 = 95950.$$

So $$X \approx 1\frac{1}{2}$$

Hence option C is correct.

i think the answer is D (1 and 1/2) not C (1 and 2/3), please check it out.
Founder
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Re: In 1986 the median home price in Danbury was approximately h [#permalink]  30 Jan 2018, 02:18
Expert's post
Peter wrote:
sandy wrote:
Explanation

The median home price in Danbury = $95950. The median home price in Trenton =$66000

So $$X \times 66000 = 95950.$$

So $$X \approx 1\frac{1}{2}$$

Hence option C is correct.

i think the answer is D (1 and 1/2) not C (1 and 2/3), please check it out.

yes, you right. Sandy wrote wrongly but the explanation is good as well as the OA.
Only he wrote C instead of D. Thank to pointed out
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Re: In 1986 the median home price in Danbury was approximately h [#permalink]  02 Feb 2018, 08:57
We have nothing to do with the data in 1st table as all the required data is available in table 2.

As prices of houses are all given as median, we need not further process them and can directly put them in the equation.

From there on, the response given by Sandy continues.
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Re: In 1986 the median home price in Danbury was approximately h [#permalink]  03 Feb 2018, 00:19
mohan514 wrote:
We have nothing to do with the data in 1st table as all the required data is available in table 2.

As prices of houses are all given as median, we need not further process them and can directly put them in the equation.

From there on, the response given by Sandy continues.

Nothing wrong with the process of solution but with the original answer choice given. I think you misinterpret my thought.
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Re: In 1986 the median home price in Danbury was approximately h [#permalink]  09 Sep 2018, 18:16
Hi, can someone give a better way to convert complicated fractions to answers. I get it was 95950/66000. When i use calculator, it was 1.45. How do I get to 1 1/2 from there?
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Re: In 1986 the median home price in Danbury was approximately h [#permalink]  10 Sep 2018, 14:41
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Expert's post
kruttikaaggarwal wrote:
Hi, can someone give a better way to convert complicated fractions to answers. I get it was 95950/66000. When i use calculator, it was 1.45. How do I get to 1 1/2 from there?

Once you get 1.45 o the calculator check the options to see which among them is th closest.
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