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If y is different from zero

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If y is different from zero [#permalink] New post 03 Sep 2019, 09:59
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Question Stats:

85% (00:06) correct 14% (01:05) wrong based on 7 sessions
If \(y \neq 0\) and \(2x+y=12\), then which of the following is NOT a possible value of x?

(A) 12

(B) 10

(C) 8

(D) 6

(E) 4
[Reveal] Spoiler: OA

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Re: If y is different from zero [#permalink] New post 04 Sep 2019, 09:11
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Carcass wrote:
If \(y \neq 0\) and \(2x+y=12\), then which of the following is NOT a possible value of x?

(A) 12

(B) 10

(C) 8

(D) 6

(E) 4


USEFUL (and often-tested) FRACTION PROPERTY: \(\frac{a-b}{c}=\frac{a}{c}-\frac{b}{c}\)

GIVEN: \(2x+y=12\)

Subtract y from both sides to get: \(2x=12-y\)

Divide both sides by 2 to get: \(x=\frac{12-y}{2}\)

Apply above PROPERTY to rewrite right sides as follows: \(x=\frac{12}{2}-\frac{y}{2}\)

Simplify: \(x=6-\frac{y}{2}\)

Since \(y \neq 0\), we can see that \(x \neq 6\), since that would require that \(y=0\)

Answer: D

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Brent
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Re: If y is different from zero [#permalink] New post 05 Sep 2019, 03:46
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5 seconds to solve. Substitute y=0, you'll get the value of x that should not be true. x=6, D
Re: If y is different from zero   [#permalink] 05 Sep 2019, 03:46
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