WRONG SOLUTION MY MISTAKE! IGNORE THIS AND SCROLL DOWNAchyuthReddy wrote:

If x, y and z are non-zero integers, and if \(x > yz\), then which of the following statements must be true?

Indicate all such statements.

A) \(\frac{x}{y} > z\)

B) \(\frac{x}{z} > y\)

C) \(\frac{x}{yz} > 1\)

d) \(yz < x\)

Since it is mentioned that x, y and z are positive you can divide them without flipping the inequality.

Given: \(x > yz\)

Dividing both sides with y

\(\frac{x}{y} > \frac{yz}{y}\) or \(\frac{x}{y} > z\)... So A is true

Dividing both sides with z

\(\frac{x}{z} > \frac{yz}{z}\) or \(\frac{x}{z} > y\)... So B is true

Dividing both sides with yy

\(\frac{x}{yz} > \frac{yz}{yz}\) or \(\frac{x}{yz} > 1\)... So C is true

Option D cant be true as it is a direct contradiction of the stement given in problem.

_________________

Sandy

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