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50% (00:55) correct
50% (00:57) wrong based on 10 sessions
x > y
Quantity A
Quantity B
The average (arithmetic mean) of x, x, x, y, and y
The average (arithmetic mean) of x, x, and y
A) Quantity A is greater. B) Quantity B is greater. C) The two quantities are equal. D) The relationship cannot be determined from the information given.
One can also investigate intuitively without doing any calculation that fewer x's being in the mean average when x is greater will ALWAYS be greater when there are fewer comparative numbers.
One can also investigate intuitively without doing any calculation that fewer x's being in the mean average when x is greater will ALWAYS be greater when there are fewer comparative numbers.
Sounds reasonable - I think Can you provide an example or two?
Cheers, Brent
_________________
Brent Hanneson – Creator of greenlighttestprep.com Sign up for my free GRE Question of the Dayemails
Greenlighttestprep - I suppose I'm not too helpful on the explanation. I just used reason, which Sandy clearly illustrated. Let's assume you have x > y and there is the mean of x,y for A and the mean of x,x,y for B, you'd get a similar answer. Essentially, more power is given to the higher number when the mean has a more substantial ratio between the higher and lower number. I don't have a mathematical proof, but I can put it together logically.
Greenlighttestprep - I suppose I'm not too helpful on the explanation. I just used reason, which Sandy clearly illustrated. Let's assume you have x > y and there is the mean of x,y for A and the mean of x,x,y for B, you'd get a similar answer. Essentially, more power is given to the higher number when the mean has a more substantial ratio between the higher and lower number. I don't have a mathematical proof, but I can put it together logically.
Sounds perfect to me! Thanks for the clarification!
Cheers, Brent
_________________
Brent Hanneson – Creator of greenlighttestprep.com Sign up for my free GRE Question of the Dayemails
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50% (00:55) correct
