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If x \sqrt[5]{-37}, the which of the following must be true

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If x \sqrt[5]{-37}, the which of the following must be true [#permalink] New post 13 Nov 2018, 11:53
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If \(x=\sqrt[5]{-37}\) then which of the following must be true?

A) \(\sqrt{- x}>2\)

B) \(x >−2\)

C) \(x^2<4\)

D) \(x^3<−8\)

E) \(x^4>32\)
[Reveal] Spoiler: OA

Last edited by Carcass on 13 Nov 2018, 14:59, edited 1 time in total.
Edited by Carcass
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Re: If x \sqrt[5]{-37}, the which of the following must be true [#permalink] New post 13 Nov 2018, 15:02
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Please format the question the proper way. It is crucial. A screenshot does not help.

read this how to do. It is not difficult
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Re: If x \sqrt[5]{-37}, the which of the following must be true [#permalink] New post 16 Nov 2018, 17:58
Can anyone provide explanation.
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Re: If x \sqrt[5]{-37}, the which of the following must be true [#permalink] New post 19 Nov 2018, 14:41
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\(x=\sqrt[5]{-37}\) can be rewitten as \(x^5=-37\). Now \((-2)^5=-32\) and \((-3)^5=-243\).

Hence x lies between \(-2\) and \(-3\). Now exmine all options one by one, only option D fits.
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Re: If x \sqrt[5]{-37}, the which of the following must be true [#permalink] New post 27 Nov 2018, 06:55
can i see the explanation
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Re: If x \sqrt[5]{-37}, the which of the following must be true [#permalink] New post 27 Nov 2018, 10:30
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Dear Sir,

sandy already provided it.

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Re: If x \sqrt[5]{-37}, the which of the following must be true   [#permalink] 27 Nov 2018, 10:30
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