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# If x \sqrt[5]{-37}, the which of the following must be true

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Manager
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If x \sqrt[5]{-37}, the which of the following must be true [#permalink]  13 Nov 2018, 11:53
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Question Stats:

66% (00:41) correct 33% (00:56) wrong based on 18 sessions
If $$x=\sqrt[5]{-37}$$ then which of the following must be true?

A) $$\sqrt{- x}>2$$

B) $$x >−2$$

C) $$x^2<4$$

D) $$x^3<−8$$

E) $$x^4>32$$
[Reveal] Spoiler: OA

Last edited by Carcass on 13 Nov 2018, 14:59, edited 1 time in total.
Edited by Carcass
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Re: If x \sqrt[5]{-37}, the which of the following must be true [#permalink]  13 Nov 2018, 15:02
Expert's post
Please format the question the proper way. It is crucial. A screenshot does not help.

read this how to do. It is not difficult
Attachments

LaTeX_Symbols.pdf [255.35 KiB]

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Re: If x \sqrt[5]{-37}, the which of the following must be true [#permalink]  16 Nov 2018, 17:58
Can anyone provide explanation.
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Re: If x \sqrt[5]{-37}, the which of the following must be true [#permalink]  19 Nov 2018, 14:41
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Expert's post
$$x=\sqrt[5]{-37}$$ can be rewitten as $$x^5=-37$$. Now $$(-2)^5=-32$$ and $$(-3)^5=-243$$.

Hence x lies between $$-2$$ and $$-3$$. Now exmine all options one by one, only option D fits.
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Re: If x \sqrt[5]{-37}, the which of the following must be true [#permalink]  27 Nov 2018, 06:55
can i see the explanation
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Re: If x \sqrt[5]{-37}, the which of the following must be true [#permalink]  27 Nov 2018, 10:30
Expert's post
Dear Sir,

Regards
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Re: If x \sqrt[5]{-37}, the which of the following must be true   [#permalink] 27 Nov 2018, 10:30
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