The distance from \(5\) = \(2x\)

and the distance from \(15 = x\)

The distance between \(15\) and\(5\)= \(15 - 5 = 10\)

That means \(2x + x = 10\)

or \(3x = 10\)

or \(x = \frac{10}{3}\)

or \(2x = \frac{20}{3}\)

Now we can calulate the value of \(x\) in \(2\)ways

i.e.\(5 + 2x = 5 + \frac{20}{3} = \frac{35}{3} = 11{\frac{2}{3}}\)

or \(15 - x = 15 - \frac{10}{3} = \frac{35}{3}= 11{\frac{2}{3}}\)
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