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If x is divisible by both 3 and 4, then the number x must be

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If x is divisible by both 3 and 4, then the number x must be [#permalink] New post 20 Apr 2018, 11:24
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If x is divisible by both 3 and 4, then the number x must be a multiple of which one of the following?

(A) 8
(B) 12
(C) 15
(D) 18
(E) 21
[Reveal] Spoiler: OA

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Re: If x is divisible by both 3 and 4, then the number x must be [#permalink] New post 08 May 2018, 03:54
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I got the answer right but I belive the way I made my pattern for the solution of this question is was pedestrian- if anyone could solve it in a more slick manner then it is most welcome.

For me I made two equation

X=3k+0---eq 1
X=4K+0
now multile of 3 as per eq 1 are as follows
3,6,9,12,15,18,21,24,27,30--- as we can see 12 and 24 can be dividend completely by 12 which is 3*4 hence I chose the answer B..

this took TIME ..any shortcut pls welcome

Last edited by IshanGre on 09 May 2018, 05:14, edited 1 time in total.
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Re: If x is divisible by both 3 and 4, then the number x must be [#permalink] New post 08 May 2018, 12:22
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3*4=12

12-24-48......and so forth

B is the answer.

OR

The only number that has 3 and 4 as factors among the answer choices is 12. The others do not.

OR

because the factors are 3 and 4 the number must be even. So, C and E are out. 8 is 2^3 and 18 is 3^2 * 2. In 8 is missing the 3 and in the latter is missing the 4.

Hope is clear now.

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Re: If x is divisible by both 3 and 4, then the number x must be [#permalink] New post 08 May 2018, 19:39
this means number x is a multiple of 12 (answer), 3 and 4, right?
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Re: If x is divisible by both 3 and 4, then the number x must be [#permalink] New post 09 May 2018, 05:19
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kruttikaaggarwal wrote:
this means number x is a multiple of 12 (answer), 3 and 4, right?



Yeah right , because if a number is a multiple of any two number then those numbers must be its factors ..hence in this case least common multiple of 3 and 4 is 12 :) .. X has to be a multiple of 12.
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Re: If x is divisible by both 3 and 4, then the number x must be [#permalink] New post 09 May 2018, 05:21
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Carcass wrote:
3*4=12

12-24-48......and so forth

B is the answer.

OR

The only number that has 3 and 4 as factors among the answer choices is 12. The others do not.

OR

because the factors are 3 and 4 the number must be even. So, C and E are out. 8 is 2^3 and 18 is 3^2 * 2. In 8 is missing the 3 and in the latter is missing the 4.



Hope is clear now.

Regards




I like your second approach ..this comes by being mindful of the question asked. KUDOS.
Re: If x is divisible by both 3 and 4, then the number x must be   [#permalink] 09 May 2018, 05:21
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