ExplanationTo solve this problem with examples, make a short list of possibilities for each of x and y:

x = 18, 36, 54…

y = 12, 24, 36…

Now try to disprove the statements by trying several combinations of x and y above. In the 1st statement, x + y could be 18 + 12 = 30, 54 + 12 = 66, 36 + 24 = 60, or many other combinations.

All of those combinations are multiples of 6. This makes sense, as x and y individually are multiples of 6, so their sum is, too. The first statement is true.

To test the second statement, xy could be 18(12) = 216, which is not divisible by 48. Eliminate the second statement.

As for the third statement, \(\frac{x}{y}\) could be \(\frac{18}{12}\), which is not even an integer (and therefore not divisible by 6), so the third statement is not necessarily true.

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Sandy

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