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If x can have only the values —3. 0, and 2, and y can have o
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09 Jun 2018, 08:29

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Question Stats:

If x can have only the values -3, 0, and 2, and y can have only the values -4, 2, and 3, what is the greatest possible value for \(2x + y^2\)?

(A) 13

(B) 15

(C) 16

(D) 20

(E) 22

_________________

(A) 13

(B) 15

(C) 16

(D) 20

(E) 22

_________________

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Re: If x can have only the values —3. 0, and 2, and y can have o
[#permalink]
09 Jun 2018, 11:11

1

Carcass wrote:

If x can have only the values -3, 0, and 2, and y can have only the values -4, 2, and 3, what is the greatest possible value for \(2x + y^2\)?

(A) 13

(B) 15

(C) 16

(D) 20

(E) 22

(A) 13

(B) 15

(C) 16

(D) 20

(E) 22

Take \(2x + y^2\) = > 2(2) + 16 ( here x = 2 that is max value and since y is square we can take largest -ve i.e. -4).

Ans D

Re: If x can have only the values —3. 0, and 2, and y can have o
[#permalink]
24 Jul 2018, 20:11

1

Carcass wrote:

If x can have only the values -3, 0, and 2, and y can have only the values -4, 2, and 3, what is the greatest possible value for \(2x + y^2\)?

(A) 13

(B) 15

(C) 16

(D) 20

(E) 22

(A) 13

(B) 15

(C) 16

(D) 20

(E) 22

we can analyse the value of x and y:

x = - 3.....0.............2

y = -4......2.............3

Given

\(2x + y^2\)

See we have \(y^2\) that can make negative value to positive. So, highest value for y must be -4. For x we have to take positive value.

\(2x + y^2\)

= \(2*2 + (-4)^2\)

= 20

The best answer is D.

Re: If x can have only the values —3. 0, and 2, and y can have o
[#permalink]
24 Sep 2021, 12:23

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