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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # If x and y are integers, and w = x^2y + x + 3y, which  Question banks Downloads My Bookmarks Reviews Important topics
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Senior Manager Joined: 20 May 2014
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If x and y are integers, and w = x^2y + x + 3y, which [#permalink] 00:00

Question Stats: 37% (01:57) correct 62% (00:55) wrong based on 8 sessions
If x and y are integers, and $$w = x^2y + x + 3y$$, which of the following statements must be true?

Indicate all such statements.

A. If w is even, then x must be even.
B. If x is odd, then w must be odd.
C. If y is odd, then w must be odd.
D. If w is odd, then y must be odd.

Kudos for correct solution.

[Reveal] Spoiler: OA
A, B, and C
[Reveal] Spoiler: OA Manager  Joined: 15 Jan 2018
Posts: 147
GMAT 1: Q V
Followers: 3

Kudos [?]: 182  , given: 0

Re: If x and y are integers, and w = x^2y + x + 3y, which [#permalink]
1
KUDOS
A good technique for problems asking what must be true is to try and make them not true. If you can't, it must be true. Also, a good technique for odd/even questions is to just test using your own odd and even numbers. Since every odd number will behave the same as every other in regards to oddness or evenness, it doesn't matter what number you choose. I like to use 0 and 1 for even and odd, respectively, since they tend to make the math very simple.

Also, it seems like a good idea to factor the equation since they probably didn't give it to us in the easiest format. One way to factor it is

y(3 + x^2) + x

A: I'll try to find a way to make w even when x is odd. Plugging in 1 for x gets me 4y + 1. It doesn't matter what y is; what we've got here is an even number plus 1, which must be odd. So there's no way to make an even number if x is odd. Thus A is in.

B: Well we just tried making x odd and found that w must be odd if x is, so B is in.

C: Let's see what happens if we substitute y for 1: We'll get 1(3 + x^2) + x or just x^2 + x + 3. We'll need to check what happens when x is odd and when x is even:
If x is 0, we get 0 + 0 + 3, which is odd.
If x is 1, we get 1 + 1 + 3, which is odd.
So it looks like C is in as well.

D: Let's try making y even and see whether we can get w to be odd:
If we make y = 0, we'll have 0(3 + x^2) + x, which is just x. So if we pick x to be odd, then w would be odd. And since we got an odd w with an even y, D is out.
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Need help with GRE math? Check out our ground-breaking books and app. Re: If x and y are integers, and w = x^2y + x + 3y, which   [#permalink] 21 Feb 2018, 10:56
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# If x and y are integers, and w = x^2y + x + 3y, which  Question banks Downloads My Bookmarks Reviews Important topics Powered by phpBB © phpBB Group Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.