Carcass wrote:

If \(\frac{x}{3} - \frac{x}{6} + \frac{x}{9} - \frac{x}{12} = 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4}\) , then \(x =\)

A. \(3\)

B. \(1\)

C. \(\frac{1}{3}\)

D. \(-\frac{1}{3}\)

E. \(-3\)

Explanation::\(\frac{x}{3} - \frac{x}{6} + \frac{x}{9} - \frac{x}{12} = 1 - \frac{1}{2} + \frac{1}{3} - \frac{1}{4}\)

\(\frac{7x}{36} = \frac{7}{12}\)

or x = 3

_________________

If you found this post useful, please let me know by pressing the Kudos Button