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# If (x + 2)(x — 3) = 0

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If (x + 2)(x — 3) = 0 [#permalink]  03 Feb 2017, 02:44
Expert's post
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Question Stats:

78% (00:39) correct 21% (00:52) wrong based on 33 sessions

If (x + 2)(x — 3) = 0 and $$x > \frac{1}{2}$$, what is the value of $$x^{-2}$$ ?

A) $$-\frac{1}{4}$$

B) $$-\frac{1}{9}$$

C) $$zero$$

D) $$\frac{1}{9}$$

E) $$\frac{1}{4}$$
[Reveal] Spoiler: OA

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Re: If (x + 2)(x — 3) = 0 [#permalink]  15 Feb 2017, 19:59
Expert's post
Explanation

Here we have equation $$(x + 2)(x — 3) = 0$$. This equation is ratified for two values of x namely -2 and 3.

Also $$x > \frac{1}{2}$$. Thus only x = 3 satisfies both the equations.

$$x^{-2}= 3^{-2} = \frac{1}{9}$$

Hence option D is correct.
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Re: If (x + 2)(x — 3) = 0   [#permalink] 15 Feb 2017, 19:59
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