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# If x = 10a, y = 3b, z = 7c, and x : y : z = 10 : 3 : 7, then

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If x = 10a, y = 3b, z = 7c, and x : y : z = 10 : 3 : 7, then [#permalink]  14 Apr 2019, 01:40
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100% (01:33) correct 0% (00:00) wrong based on 1 sessions
If $$x = 10a$$, $$y = 3b$$, $$z = 7c$$, and $$x : y : z = 10 : 3 : 7$$, then $$\frac{7x+2y+5x}{8a+b+3c}=$$

(A) $$\frac{111}{12}$$

(B) $$\frac{7}{6}$$

(C) $$\frac{8}{15}$$

(D) $$\frac{108}{123}$$

(E) $$\frac{135}{202}$$
[Reveal] Spoiler: OA

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If x = 10a, y = 3b, z = 7c, and x : y : z = 10 : 3 : 7, then   [#permalink] 14 Apr 2019, 01:40
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# If x = 10a, y = 3b, z = 7c, and x : y : z = 10 : 3 : 7, then

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