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If x > 0 and

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Intern
Intern
Joined: 22 Aug 2016
Posts: 32
Followers: 0

Kudos [?]: 9 [0], given: 5

If x > 0 and [#permalink] New post 06 Jan 2017, 08:12
00:00

Question Stats:

85% (00:51) correct 14% (01:29) wrong based on 7 sessions
I got the answer right but Im not sure regarding the method I used. Any ideas how to solve this?

Thanks
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1 KUDOS received
GMAT Club Legend
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Joined: 07 Jun 2014
Posts: 4722
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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Kudos [?]: 1630 [1] , given: 390

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Re: If x > 0 and [#permalink] New post 06 Jan 2017, 16:14
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Expert's post
Hey,

This question is pretty straight forward.
We have

\(\frac{x}{y}\sqrt{\frac{y}{x^2}}\)

rewritten as

\(\sqrt{\frac{x}{y}} \times \sqrt{\frac{x}{y}} \times \sqrt{\frac{y}{x}}\times\sqrt{\frac{1}{x}}\)

cancelling out \(\sqrt{\frac{x}{y}}\) and \(\sqrt{\frac{y}{x}}\)

As x > 0 and y > 0 \(\sqrt{x}\) and \(\sqrt{y}\) are defined and \(\frac{x}{y}\) and \(\frac{y}{x}\) are also defined.

\(\sqrt{\frac{x}{y}} \times \sqrt{\frac{1}{x}}\)

cancelling out \(\sqrt{x}\)

\(\sqrt{\frac{1}{y}}\)

Hence E is the correct answer.
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Sandy
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Re: If x > 0 and   [#permalink] 06 Jan 2017, 16:14
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