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# If x > 0 and

Author Message
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Intern
Joined: 22 Aug 2016
Posts: 32
Followers: 0

Kudos [?]: 9 [0], given: 5

If x > 0 and [#permalink]  06 Jan 2017, 08:12
00:00

Question Stats:

85% (00:51) correct 14% (01:29) wrong based on 7 sessions
I got the answer right but Im not sure regarding the method I used. Any ideas how to solve this?

Thanks
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Bildschirmfoto 2017-01-06 um 17.11.04.png [ 30.95 KiB | Viewed 1248 times ]

GMAT Club Legend
Joined: 07 Jun 2014
Posts: 4722
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 91

Kudos [?]: 1630 [1] , given: 390

Re: If x > 0 and [#permalink]  06 Jan 2017, 16:14
1
KUDOS
Expert's post
Hey,

This question is pretty straight forward.
We have

$$\frac{x}{y}\sqrt{\frac{y}{x^2}}$$

rewritten as

$$\sqrt{\frac{x}{y}} \times \sqrt{\frac{x}{y}} \times \sqrt{\frac{y}{x}}\times\sqrt{\frac{1}{x}}$$

cancelling out $$\sqrt{\frac{x}{y}}$$ and $$\sqrt{\frac{y}{x}}$$

As x > 0 and y > 0 $$\sqrt{x}$$ and $$\sqrt{y}$$ are defined and $$\frac{x}{y}$$ and $$\frac{y}{x}$$ are also defined.

$$\sqrt{\frac{x}{y}} \times \sqrt{\frac{1}{x}}$$

cancelling out $$\sqrt{x}$$

$$\sqrt{\frac{1}{y}}$$

Hence E is the correct answer.
_________________

Sandy
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Re: If x > 0 and   [#permalink] 06 Jan 2017, 16:14
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