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If x = 0.888, y = \0.888 , and z = (0.888)^2

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Carcass

Verbal Expert

Joined: 18 Apr 2015

Posts: 16587

GRE 1: Q160 V160

If x = 0.888, y = \0.888 , and z = (0.888)^2 [#permalink]

24 Aug 2018, 15:29

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If \(x = 0.888\), \(y = \sqrt{0.888}\) , and \(z = (0.888)^2\), then which of the following is true?

(A) x < y < z

(B) x < z < y

(C) y < x < z

(D) y < z < x

(E) z < x < y

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towhid

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Joined: 24 Aug 2018

Posts: 1

Re: If x = 0.888, y = \0.888 , and z = (0.888)^2 [#permalink]

24 Aug 2018, 16:50

Ans: (E)

pranab223

Joined: 20 Apr 2016

Posts: 1306

WE:Engineering (Energy and Utilities)

Re: If x = 0.888, y = \0.888 , and z = (0.888)^2 [#permalink]

26 Aug 2018, 08:32

Carcass wrote:

If \(x = 0.888\), \(y = \sqrt{0.888}\) , and \(z = (0.888)^2\), then which of the following is true?

(A) x < y < z

(B) x < z < y

(C) y < x < z

(D) y < z < x

(E) z < x < y

Here,

\({0.888}^2\) = will always be less than \(0.888\)

\(\sqrt{0.888}\)= will always be greater than the \(0.888\)

So it can be arranged as

\(z < x < y\) i.e. option E
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