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If x = 0.888, y = \0.888 , and z = (0.888)^2
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Carcass
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Joined: 18 Apr 2015
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GRE 1: Q160 V160
If x = 0.888, y = \0.888 , and z = (0.888)^2 [#permalink] New post  24 Aug 2018, 15:29
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If \(x = 0.888\), \(y = \sqrt{0.888}\) , and \(z = (0.888)^2\), then which of the following is true?

(A) x < y < z

(B) x < z < y

(C) y < x < z

(D) y < z < x

(E) z < x < y
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Re: If x = 0.888, y = \0.888 , and z = (0.888)^2 [#permalink] New post  24 Aug 2018, 16:50
Ans: (E)
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Re: If x = 0.888, y = \0.888 , and z = (0.888)^2 [#permalink] New post  26 Aug 2018, 08:32
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Carcass wrote:
If \(x = 0.888\), \(y = \sqrt{0.888}\) , and \(z = (0.888)^2\), then which of the following is true?

(A) x < y < z

(B) x < z < y

(C) y < x < z

(D) y < z < x

(E) z < x < y



Here,

\({0.888}^2\) = will always be less than \(0.888\)

\(\sqrt{0.888}\)= will always be greater than the \(0.888\)

So it can be arranged as

\(z < x < y\) i.e. option E
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