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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here. # If which x < y < 0, of the following inequalities must be tr  Question banks Downloads My Bookmarks Reviews Important topics
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TAGS: Founder  Joined: 18 Apr 2015
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If which x < y < 0, of the following inequalities must be tr [#permalink]
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Expert's post 00:00

Question Stats: 52% (01:26) correct 47% (01:03) wrong based on 189 sessions
Founder  Joined: 18 Apr 2015
Posts: 13918
GRE 1: Q160 V160 Followers: 315

Kudos [?]: 3687 , given: 12942

Re: If which x < y < 0, of the following inequalities must be tr [#permalink]
Expert's post
Solution

The question could become complex to evaluate theoretically. So the best way is to pick numbers

The stem can be tricky: it does not say that the numbers $$MUST$$ be integers. As such, you need to take in account both options:$$X= -2$$ and $$Y=-1$$ OR $$X=\frac{-3}{2}$$ and $$Y=\frac{-1}{2}$$

Testing all the answer choices we will end up that E will be $$-3<4$$ and it is true;$$\frac{3}{4}<\frac{9}{4}$$ and this is also true

The correct answer is $$E$$
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Re: If which x < y < 0, of the following inequalities must be tr [#permalink]
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Expert's post
Carcass wrote:
If which $$x < y < 0$$, of the following inequalities must be true?

 A $$y + 1 < x$$
 B $$y - 1 < x$$
 C $$xy^2 < x$$
 D $$xy < y^2$$
 E $$xy < x^2$$

We can see that both x and y are negative, and y is greater than x. So A is not true. B is not true, either, since we don’t know how much y is greater than x. If we divide both sides by x in the inequality in C (and switch the inequality sign since x is negative), we have:

y^2 > 1

However, since we don’t know the value of y, we can’t determine whether its square is in fact greater than 1. So C might not be true. If we divide both sides by y in the inequality in D (and switch the inequality sign since y is negative), we have:

x > y

This is not true since we know y > x. So the correct answer must be E. However, let’s verify it by dividing both sides of the inequality by x:

y > x

This is true since we know y is indeed greater than x.

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# Jeffrey Miller

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Re: If which x < y < 0, of the following inequalities must be tr [#permalink]
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Carcass wrote:
If which $$x < y < 0$$, of the following inequalities must be true?

 A $$y + 1 < x$$
 B $$y - 1 < x$$
 C $$xy^2 < x$$
 D $$xy < y^2$$
 E $$xy < x^2$$

Practice Questions
Question: 24
Page: 463
Difficulty: medium/hard

Given

$$x < y < 0$$

Here we understand that x is the most negative between x and y. So, whenever we square it , we get the maximum value which is greater than y.

Thus the best answer is E. Intern Joined: 23 Sep 2018
Posts: 6
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Re: If which x < y < 0, of the following inequalities must be tr [#permalink]
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Please correct the OA here. It is "E"
Manager Joined: 23 Oct 2018
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Re: If which x < y < 0, of the following inequalities must be tr [#permalink]
is there an explanation
Founder  Joined: 18 Apr 2015
Posts: 13918
GRE 1: Q160 V160 Followers: 315

Kudos [?]: 3687 , given: 12942

Re: If which x < y < 0, of the following inequalities must be tr [#permalink]
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Re: If which x < y < 0, of the following inequalities must be tr [#permalink]
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Expert's post
Carcass wrote:
If which $$x < y < 0$$, of the following inequalities must be true?

A $$y + 1 < x$$

B $$y - 1 < x$$

C $$xy^2 < x$$

D $$xy < y^2$$

E $$xy < x^2$$

Practice Questions
Question: 24
Page: 463
Difficulty: medium/hard

The question asks, "What MUST be true?"

So if we can find a case in which an answer choice is NOT true, then we can ELIMINATE that answer choice.

GIVEN: x < y < 0

A) y + 1 < x
If x < y < 0, then it's possible that x = -3 and y = -1
When plug these values into the above inequality, we get: -1 + 1 < -3
Simplify to get: 0 < -3, which is NOT true
ELIMINATE A

B) y - 1 < x
If x < y < 0, then it's possible that x = -3 and y = -1
When plug these values into the above inequality, we get: -1 - 1 < -3
Simplify to get: -2 < -3, which is NOT true
ELIMINATE B

C) xy < x
If x < y < 0, then it's possible that x = -3 and y = -1
When plug these values into the above inequality, we get: (-3)(-1) < -3
Simplify to get: 3 < -3, which is NOT true
ELIMINATE C

D) xy < y²
If x < y < 0, then it's possible that x = -3 and y = -1
When plug these values into the above inequality, we get: (-3)(-1) < (-1)²
Simplify to get: 3 < 1, which is NOT true
ELIMINATE D

By the process of elimination, the correct answer must be E

Cheers,
Brent
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Brent Hanneson – Creator of greenlighttestprep.com Moderator Joined: 18 Oct 2018
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Re: If which x < y < 0, of the following inequalities must be tr [#permalink]
[quote="Carcass"]If which $$x < y < 0$$, of the following inequalities must be true?

A $$y + 1 < x$$

B $$y - 1 < x$$

C $$xy^2 < x$$

D $$xy < y^2$$

E $$xy < x^2$$

multiply both the sides with x to get x^2 > xy. -- sign changes because x is negative. Re: If which x < y < 0, of the following inequalities must be tr   [#permalink] 06 Dec 2019, 11:07
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