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If the volume of one cube is 8 times greater than that of an

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If the volume of one cube is 8 times greater than that of an [#permalink] New post 24 Mar 2020, 08:49
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If the volume of one cube is 8 times greater than that of another, what is the ratio of the area of one square face of the larger cube to that of the smaller cube?

(A) 16:1
(B) 12:1
(C) 8:1
(D) 4:1
(E) 2:1
[Reveal] Spoiler: OA
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Re: If the volume of one cube is 8 times greater than that of an [#permalink] New post 25 Mar 2020, 16:04
Expert's post
The volume of the smaller cube = \(x^3\)

The volume of the bigger cube = \(8*x^3\)

To find the side of the biggest cube =\(∛(8*x^3) = 2x\)

Find the Area of one face of smaller cube = \(x*x = x^2\)

Find the Area of one face of larger cube = \(2x*2x=4x^2\)

Therefore, the ratio is 4:1

D is the answer
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Re: If the volume of one cube is 8 times greater than that of an   [#permalink] 25 Mar 2020, 16:04
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If the volume of one cube is 8 times greater than that of an

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