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If the probability that the first event will occur is , and

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GRE Prep Club Legend
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Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
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If the probability that the first event will occur is , and [#permalink] New post 24 Nov 2017, 20:52
Expert's post
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Question Stats:

85% (01:48) correct 14% (01:19) wrong based on 14 sessions
If the probability that the first event will occur is \(\frac{1}{4}\), and the probability that the second event will occur is \(1 \div \sqrt{x+2}\), then what is the probability that both events will occur?

A. \(\sqrt{x+2} \div (4x + 8)\)
B. \(\sqrt{x+2} \div 4\)
C. \(\sqrt{x+2} \div (16x + 32)\)
D. \(4 \div \sqrt{x+2}\)
E. \(4 \times \sqrt{x+2}\)

Drill 2
Question: 3
Page: 524
[Reveal] Spoiler: OA

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Re: If the probability that the first event will occur is , and [#permalink] New post 02 Dec 2017, 07:36
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sandy wrote:
If the probability that the first event will occur is \(\frac{1}{4}\), and the probability that the second event will occur is \(1 \div \sqrt{x+2}\), then what is the probability that both events will occur?

A. \(\sqrt{x+2} \div (4x + 8)\)
B. \(\sqrt{x+2} \div 4\)
C. \(\sqrt{x+2} \div (16x + 32)\)
D. \(4 \div \sqrt{x+2}\)
E. \(4 \times \sqrt{x+2}\)

Drill 2
Question: 3
Page: 524



The event occuring together P(A and B) = P(A) * P (B)

here we write as p(\(\frac{1}{4}\) and \(1 \div \sqrt{x+2}\) ) = \(\frac{1}{4}\) * \(\frac{1}{{\sqrt{x+2}}}\)

or we can write as = \(\frac{1}{4}\) * \(\frac{1}{{\sqrt{x+2}}}\) * \({\sqrt{x+2}}\div{\sqrt{x+2}}\)

or we can write as = \(\sqrt{x+2} \div (4x + 8)\) (since 4 * \(\sqrt{x+2} * \sqrt{x+2}\) = 4x + 8 )
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GRE Prep Club Legend
GRE Prep Club Legend
User avatar
Joined: 07 Jun 2014
Posts: 4857
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 105

Kudos [?]: 1776 [0], given: 397

Re: If the probability that the first event will occur is , and [#permalink] New post 29 Dec 2017, 13:17
Expert's post
Explanation

Plug In to make this problem much simpler. If you plug in x = 2, then the probability for the second event is: \(1 \div \sqrt{4}=\frac{1}{2}\).

Now, because this is an “and” probability problem, you multiply the two probabilities together to find the target answer:

\(\frac{1}{4}\times \frac{1}{2}=\frac{1}{8}\).

Choice A is the only one that works.
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Re: If the probability that the first event will occur is , and   [#permalink] 29 Dec 2017, 13:17
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If the probability that the first event will occur is , and

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