Least common multiple of \(m\) and \(n\) is 24.

So for a number larger than 3070 to be divisible by both \(m\) and \(n\), it must be divisible by the least common multiple of m and n as well.

Using the gre calculator \(\frac{3070}{24}=127.9166\).

Clearly multiple of 24 larger than 3070 is \(128 \times 24=3072\).
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24=23∗324=23∗3

As per divisibility rule -

1. For a number to be divisible by 8, the last 3 digits must be divisible by 8.
2. For a number to be divisible by 3, the sum of the digits must be divisible by 3.

Check the options only (A) follows

1. 072 - Divisible by 8
2. 3072 - Sum of the digits is 12 , which is divisible by 3

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