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# If the integer x is divisible by 3 but not by

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Senior Manager
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If the integer x is divisible by 3 but not by [#permalink]  11 Jul 2018, 07:36
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85% (00:15) correct 14% (00:53) wrong based on 7 sessions
If the integer x is divisible by 3 but not by 2, then which one of the following is never a integer?

A $$\frac{x+1}{2}$$

B $$\frac{x}{7}$$

C $$\frac{x^2}{3}$$

D $$\frac{x^3}{3}$$

E $$\frac{x}{24}$$

source: orbit test prep
[Reveal] Spoiler: OA
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Re: If the integer x is divisible by 3 but not by [#permalink]  11 Jul 2018, 10:53
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amorphous wrote:
If the integer x is divisible by 3 but not by 2, then which one of the following is never a integer?

A $$\frac{x+1}{2}$$

B $$\frac{x}{7}$$

C $$\frac{x^2}{3}$$

D $$\frac{x^3}{3}$$

E $$\frac{x}{24}$$

source: orbit test prep

Here,
As the question tells us that x is not divisible by 2 then we have to look the denominator any even value divisible by 2 will give the answer.

But here we are left with 2 option. Option A and Option E

In option A , the number $$\frac{x+1}{2}$$ will be divisible by 2, since the numerator: x + 1 = Even number (since x is odd, so Odd + 1 = even number and it will be divisible by 2)

So we are left with option E
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Re: If the integer x is divisible by 3 but not by [#permalink]  17 Jul 2018, 08:01
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amorphous wrote:
If the integer x is divisible by 3 but not by 2, then which one of the following is never a integer?

A $$\frac{x+1}{2}$$

B $$\frac{x}{7}$$

C $$\frac{x^2}{3}$$

D $$\frac{x^3}{3}$$

E $$\frac{x}{24}$$

source: orbit test prep

Note : x is divisible by 2 not by 3. It means that x is not divisible by 6.

Option E.

x/24

= $$\frac{x}{4*6}$$

Thus option E is never a integer.

Hope it's clear.
Re: If the integer x is divisible by 3 but not by   [#permalink] 17 Jul 2018, 08:01
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