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# If the integer a is a multiple of 6, the integer b is a mult

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Director
Joined: 07 Jan 2018
Posts: 597
Followers: 7

Kudos [?]: 525 [0], given: 88

If the integer a is a multiple of 6, the integer b is a mult [#permalink]  07 Apr 2018, 19:24
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Question Stats:

100% (00:53) correct 0% (00:00) wrong based on 3 sessions
If the integer a is a multiple of 6, the integer b is a multiple of 3, and a>b>0, then which of the following integers must be $$a^2$$ – $$b^2$$ multiple of?

A)6
B)8
c)9
D)10
E)12
[Reveal] Spoiler: OA
Manager
Joined: 26 Jan 2018
Posts: 176
Followers: 0

Kudos [?]: 105 [0], given: 3

Re: If the integer a is a multiple of 6, the integer b is a mult [#permalink]  07 Apr 2018, 21:56
On substituting the values of 6 and 3 in a and b,

a^2 – b^2 = 6^2 - 3^2 = 36-9

=27

27 is a multiple of only 9 in the answer options.
So C
Re: If the integer a is a multiple of 6, the integer b is a mult   [#permalink] 07 Apr 2018, 21:56
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