It is currently 27 Nov 2020, 08:33
My Tests

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

If the function g is defined for all nonzero numbers y b

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Founder
Founder
User avatar
Joined: 18 Apr 2015
Posts: 13909
GRE 1: Q160 V160
Followers: 315

Kudos [?]: 3680 [0], given: 12931

CAT Tests
If the function g is defined for all nonzero numbers y b [#permalink] New post 23 May 2019, 02:23
Expert's post
GRE Instructor
User avatar
Joined: 10 Apr 2015
Posts: 3907
Followers: 164

Kudos [?]: 4771 [0], given: 70

Re: If the function g is defined for all nonzero numbers y b [#permalink] New post 23 May 2019, 05:39
Expert's post
Carcass wrote:
If the function \(g\) is defined for all nonzero numbers \(y\) by \(g(y)=\frac{y}{|y|}\), find the value of each of the following.

(a) \(g(2)\)

(b) \(g(-2)\)

(c) \(g(2) -g(-2)\)

[Reveal] Spoiler: OA
(a) 1 (b) −1 (c) 2



(a) \(g(2)=\frac{2}{|2|}=\frac{2}{2}=1\)

(b) \(g(-2)=\frac{-2}{|-2|}=\frac{-2}{2}=-1\)

(c) \(g(2) - g(-2) = 1 - (-1) = 2\)

Cheers,
Brent
_________________

Brent Hanneson – Creator of greenlighttestprep.com
Image
Sign up for GRE Question of the Day emails

Re: If the function g is defined for all nonzero numbers y b   [#permalink] 23 May 2019, 05:39
Display posts from previous: Sort by

If the function g is defined for all nonzero numbers y b

  Question banks Downloads My Bookmarks Reviews Important topics  


cron

GRE Prep Club Forum Home| About| Terms and Conditions and Privacy Policy| GRE Prep Club Rules| Contact

Powered by phpBB © phpBB Group

Kindly note that the GRE® test is a registered trademark of the Educational Testing Service®, and this site has neither been reviewed nor endorsed by ETS®.