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# If the average of 10, 12, n, and n is greater than 25, what

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Joined: 07 Jun 2014
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If the average of 10, 12, n, and n is greater than 25, what [#permalink]  24 Nov 2017, 20:48
Expert's post
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Question Stats:

0% (00:00) correct 100% (00:13) wrong based on 2 sessions
If the average of 10, 12, n, and n is greater than 25, what is the least possible value of integer n ?

A. 38
B. 39
C. 40
D. 41
E. 42

Drill 1
Question: 12
Page: 523
[Reveal] Spoiler: OA

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Re: If the average of 10, 12, n, and n is greater than 25, what [#permalink]  02 Dec 2017, 11:04
sandy wrote:
If the average of 10, 12, n, and n is greater than 25, what is the least possible value of integer n ?

A. 38
B. 39
C. 40
D. 41
E. 42

Drill 1
Question: 12
Page: 523

Now we need to find the least value of n

let us take the average =

$$\frac{(10 + 12 + n + n)}{4}$$ = 25

or 22 + 2n = 100

or n = 39 . Now n cannot be 39 because the average of all these 4 nos > 25

so the least value should be 40
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GMAT Club Legend
Joined: 07 Jun 2014
Posts: 4710
GRE 1: Q167 V156
WE: Business Development (Energy and Utilities)
Followers: 90

Kudos [?]: 1606 [0], given: 375

Re: If the average of 10, 12, n, and n is greater than 25, what [#permalink]  10 Dec 2017, 17:14
Expert's post
Explaination

To find the average, divide the total by the number of values. So,$$\frac{10+12+n+n}{4}> 25.$$

Multiply both sides of the inequality by 4 and then subtract 22 (10 + 12) to find 2n > 78. Divide by 2 to find n > 39. So, n is NOT 39; it is the least integer greater than 39, which is 40.

Alternatively, you could plug in the answers starting with choice (A) because the question asks for the least possible value. If n = 38 or 39, then the average is not greater than 25. If n = 40, the average is greater than 25.

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Re: If the average of 10, 12, n, and n is greater than 25, what   [#permalink] 10 Dec 2017, 17:14
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