Carcass wrote:
If the average (arithmetic mean) of two numbers is 20 and one of the numbers is x, what is the other number in terms of x ?
(A) 40 - x
(B) 40 - 2x
(C) 20 + x
(D) 20 - x
(E) 20 - 2x
Let the other number be = y
Since,
\({Arithmetic Mean} = \frac{{Sum of numbers}}{{Total number of variables}}\)
or \(20 = \frac{{x + y}}{2}\)(since the number of variables is x and y i.e 2)
or \(x + y = 40\)
or \(y = 40 - x\)
So the other number in terms of x is = \(40 - x\)
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100% (00:22) correct
