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If the average (arithmetic mean) of two numbers is 20 and on [#permalink]
Expert's post 00:00

Question Stats: 100% (00:22) correct 0% (00:00) wrong based on 20 sessions
If the average (arithmetic mean) of two numbers is 20 and one of the numbers is x, what is the other number in terms of x ?

(A) 40 - x

(B) 40 - 2x

(C) 20 + x

(D) 20 - x

(E) 20 - 2x
[Reveal] Spoiler: OA

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Re: If the average (arithmetic mean) of two numbers is 20 and on [#permalink]
Carcass wrote:
If the average (arithmetic mean) of two numbers is 20 and one of the numbers is x, what is the other number in terms of x ?

(A) 40 - x

(B) 40 - 2x

(C) 20 + x

(D) 20 - x

(E) 20 - 2x

Let the other number be = y

Since,

$${Arithmetic Mean} = \frac{{Sum of numbers}}{{Total number of variables}}$$

or $$20 = \frac{{x + y}}{2}$$(since the number of variables is x and y i.e 2)

or $$x + y = 40$$

or $$y = 40 - x$$

So the other number in terms of x is = $$40 - x$$
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GRE Prep Club Members of the Month:TOP 10 members of the month with highest kudos receive access to 3 months GRE Prep Club tests Re: If the average (arithmetic mean) of two numbers is 20 and on   [#permalink] 12 Jul 2018, 19:16
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